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3 years ago

ANSWER THIS PLS!!!!

1 answer:

5 0

Answer and Step-by-step explanation: With the constant velocity motion formula, we can determine constant velocity of the object in motion whose data we collected:

x = x₀ + vt

Velocity can be calculated as:

$v=\frac{x-x_{0}}{t}$

$v=\frac{70-40}{10}$

v = 3 m/s

The beginning of the data collect, object is 40m away, then x₀ = 40.

So, equation modeling the object's path is x = 40 + 3t.

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In each of the following equations, what is

timama [110]

The graph will cross at the coordinates (-2, 9)

<h3>How to solve equations?</h3>

y = 3x + 15

y = 3 - 3x

y = 3x + 15

Hence,

when x = 2

y = 3(2) + 15 = 21

when x = 0

y = 3(0) + 15 = 15

y = 3 - 3x

when x = 2

y = 3 - 3(2)

y = 3 - 6

y = -3

when x = 0

y = 3 - 3(0)

y = 3

Therefore, let's check if the equation will cross.

y = 3x + 15

y = 3 - 3x

using substitution,

3 - 3x = 3x + 15

3 - 15 = 3x + 3x

- 12 = 6x

x = -12 / 6

x = -2

y = 3 - 3(-2)

y = 3 + 6

y = 9

Therefore, the graph will cross at the coordinates (-2, 9)

learn more on equations here: brainly.com/question/19297665

#SPJ1

8 0

1 year ago

Describe how you could use algebraic operations to solve the equation 1 = -3x + 4

Anna11 [10]

Answer:

x=1

Step-by-step explanation:

3x=4-1

3x=3

x=1

3 0

3 years ago

I don't understand this problem

ExtremeBDS [4]

Answer:

45%

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

We looking for distance

drek231 [11]

Answer:

240 m

Step-by-step explanation:

Figure is attached.

The distance the particle travels is the area under the v-t graph over the time interval from 0 min to 4 min. The reason you can't just multiply velocity by time is that the velocity is changing at a constant rate over the given time interval (the line is going upward--the particls is speeding up).

What's the area under the graph?

The red outline forms a trapezoid. The area of a trapezoid is $A=\frac{1}{2}h(b_1+b_2)$ where the <em>b</em>'s are the lengths of the two parallel base and <em>h</em> is the height (the distance between the bases).