<span>first, we are going to define variables as the following:
a = 0
a = π/2
n = 4 rectangles
Δx = [ b - a ] / n ------>Δx = [ π/2 - 0 ] / 4 = π/8
right endpoints :
sum( seq( 4 cos(x) * π/8 , x , 0+π/8 , π/2 , π/8 ) ) = 3.163065 underestimate
left endpoints:
sum( seq( 4 cos(x) * π/8 , x , 0 , π/2-(π/8) , π/8 ) ) = 4.733861 overestimate
the reason because the actual estimate by integral as the following:
π/2
∫ 4cos(x) dx = 4
0</span>
The answer would be 0.8, because 800 hundreds go into 8 thousandths, but there is only 80 hundreds, so the answer is 0.8 thousandths.
Answer: 0.8 thousandths
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Answer:
yes it is
Step-by-step explanation:
Answer:
$1000
Step-by-step explanation:
We can form an equation for Clayton's account: C = 500 + 10x
We can form an equation for Clayton's account: J = 400 +12x
(where x is the number of days)
When the two accounts will contain the same amount, it means: C = J
<=> 500 + 10x = 400 +12x
<=> x =50
After 50 days, there accounts will be balance. Then, we substitue x into any of the 2 equation to find out the amount: 500 + 10(50) = $1000
