Answer:
The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 67 - 4.54 = 62.46 ounches.
The upper end of the interval is the sample mean added to M. So it is 67 + 4.54 = 71.54 ounces.
The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.
n=3; We need a third degree polynomials with the following given zero's: 2 and 5i are zeros; f(-1)=156.
Since these are solutions
x = 2 ; x = 5i. Since imaginaries travel in pairs, the other answer is x= -5i.
We have (x-2)(x-5i)(x+5i) = 0
Now,
f(-1) = (-1-2)(-1-5i)(-1+5i) = 156.
f(-1) = (-3)(26) = -78.
But -78 x -2 = 156, so our polynomial becomes
Y= -2x (<em>x</em> - 2 ) x (<em>x </em>to the power of 2 + 25) = 0
The answer is the second one
Answer:
Subtract 5x from both sides of the equation.
7y=1−5x
x+4y=−5
Divide each term by 7 and simplify.
y=17−5x/7
x+4y=−5
Subtract x from both sides of the equation.
y=1/7−5x/7
4y=−5−x
y=1/7−5x/7
Divide each term by 4 and simplify.
y=1/7−5x/7
y=−5/4−x/4
y=1/7−5x/7
Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution. (3,−2)
Step-by-step explanation:
