Answer:
straight line that passes through the origin
Step-by-step explanation:
Two variables are said to have a direct variation or proportional relationship if it can be represented by y = kx, where k is a constant.
Comparing this with the equation of a straight line y = mx + b, where m is the slope of the line and b is the y intercept (value of y when x = 0), We can tell if the say that the graph of a direct variation or proportional relationship is a straight line with no y intercept (b = 0, that is it passes through the origin).
The range is: 35-60
The IQR is: 11
This value is the first 25%
IQR= interquartile range
Hope this helps ;)
Cylinder volume = PI * radius^2 * height
cylinder volume = 3.14159 * 16 * 4
cylinder volume = 3.14159 * 64
cylinder volume =
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201.06</span></span></span>
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
Answer:Her Aunt paid her 4.50 and hour and her neighbor 6 an hour. The difference is 1.5
Step-by-step explanation:
