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Goshia [24]
3 years ago
7

Alex had $693.27 in her bank account. She withdrew money from the account to pay $123.54 for her electric bill and $98.66 for gr

oceries. How much money was left in Alex's account after she made these withdrawals?
Mathematics
2 answers:
Nina [5.8K]3 years ago
8 0

Answer:

$471.07

Step-by-step explanation:

$123.54 + $98.66

=$222.2

$693.27 - 222.2

=471.07

LiRa [457]3 years ago
4 0

Answer:$471.01

Step-by-step explanation:

693.27-123.54-98.66=471.01

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If the sale price is $40 and the discount is 25%, what is the original price?
sveta [45]
Use this equation to solve the problem:

x - (x * .25) = 40

This equation is saying the original price times itself by 25% is 40.

x - (x * .25) = 40
Simplify.
x - .25x = 40
.75x = 40
Divide both sides by .75.
x = 53.33

The original price was $53.33
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3 years ago
Solve the formula d = st for s
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Step-by-step explanation:

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stealth61 [152]
S is slope
S= rise/run
S1=3/12=1/4
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2 years ago
The first quartile of the data set below is
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3 0
3 years ago
The general solution to the second-order differential equation y′′+10y=0 is in the form y(x)=c1cosβx+c2sinβx. Find the value of
allsm [11]

Answer:β=√10 or 3.16 (rounded to 2 decimal places)

Step-by-step explanation:

To find the value of β :

  • we will differentiate the y(x) equation twice to get a second order differential equation.
  • We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β

y(x)=c1cosβx+c2sinβx

we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.

Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate  βx in each case and multiply with the differential of c1cosx and c2sinx respectively.

lastly the differential of sinx= cosx and for cosx = -sinx.

Knowing all these we can proceed to solving the problem.

y=c1cosβx+c2sinβx

y'= β×c1×-sinβx+β×c2×cosβx  

y'=-c1βsinβx+c2βcosβx

y''=β×-c1β×cosβx + (β×c2β×-sinβx)

y''= -c1β²cosβx -c2β²sinβx

factorize -β²

y''= -β²(c1cosβx +c2sinβx)

y(x)=c1cosβx+c2sinβx

therefore y'' = -β²y

y''+β²y=0

now we compare this with the second order D.E provided in the question

y''+10y=0

this means that β²y=10y

β²=10

B=√10  or 3.16(2 d.p)

5 0
3 years ago
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