Answer:
195.25
Step-by-step explanation:
Consider geometric series S(n) where initial term is a
So S(n)=a+ar^1+...ar^n
Factor out a
S(n)=a(1+r+r^2...+r^n)
Multiply by r
S(n)r=a(r+r^2+r^3...+r^n+r^n+1)
Subtract S(n) from S(n)r
Note that only 1 and rn^1 remain.
S(n)r-S(n)=a(r^n+1 -1)
Factor out S(n)
S(n)(r-1)=a(r^n+1 -1)
The formula now shows S(n)=a(r^n+1 -1)/(r-1)
Now use the formula for the problem
Answer:
Step-by-step explanation:
Domain:all real values
Range:[5,∞)
Answer:
50%
Step-by-step explanation:
duhh, sorry this one just very obvious
We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA=

. Hence CM=GC+GM=3*

. Now, since GM is normal to AB, we have by the pythagoeran theorem that:

Hence, we calculate from this that AC^2= 28, hence AC=2*

=BC. Thus, the perimeter of the triangle is 2+4*

.