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m_a_m_a [10]
3 years ago
6

Given a balanced chemical equation it is always possible to determine

Chemistry
1 answer:
Alborosie3 years ago
8 0

Answer:

C)  the relative number of moles taking part in the reaction

Explanation:

From a balanced chemical equation, it is always possible to determine the relative number of moles taking part in a chemical reaction.

The number of moles is the amount of the reacting specie that makes up a chemical reaction.

  • In balanced chemical equation, the number of moles of reactants and products must be the same.
  • From this understanding, we can determine the amount of reactants and products needed for a chemical reaction to take place.
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How many atoms are in 162.0 g of magnesium? ​
lidiya [134]

Answer:

3,938.22

Explanation:

(correct me if I'm wrong)

4 0
3 years ago
On the surface of earth where is calculated by what
miv72 [106K]

On the surface of the earth, weight is calculated by multiplying mass and gravity. Because we know the radius of the Earth, we can use the Law of Universal Gravitation to calculate the mass of the Earth in terms of the gravitational force on an object (its weight) at the Earth's surface, using the radius of the Earth as the distance.

I think this is the question you were trying to ask if not, ill try it again

6 0
3 years ago
In central Texas, in the area known as the Texas Hill Country, is the Edwards Plateau ecoregion and Llano Uplift ecoregion. The
ra1l [238]

Answer: chemical weathering

Explanation:

8 0
3 years ago
The reaction described by the equation CH 3 Cl + NaOH → CH 3 OH + NaCl follows the second-order rate law, rate = k [ CH 3 Cl ] [
fredd [130]

Answer:

The rate is 4,5 \times 10^{-5}\frac{mole}{Ls}

Explanation:

Stoichiometry

CH_{3}Cl+NaOH \rightarrow CH_{3}OH+NaCl

Kinetics

-r_{A}=k \times [CH_{3}Cl] \times [NaOH]

The rate constant K can be calculated by replacing with the initial data

1 \times 10^{-4}\frac{mole}{Ls}=k \times [0,2M] \times [1,0M]  =5 \times 10^{-4}\frac{L}{mole s}

Taking as a base of calculus 1L, when half of the CH_{3}Cl is consumed the mixture is composed by

0,1 mole CH_{3}Cl (half is consumed)

0,9 mole NaOH (by stoicheometry)

0,1 mole CH_{3}OH  

0,1 mole NaCl

Then, the rate is

-r_{A}=5 \times 10^{-4} \frac{L}{mole s}\times 0,1M \times 0,9 M=4,5 \times 10^{-5}\frac{mole}{Ls}

The reaction rate decreases because there’s a smaller concentration of reactives.

6 0
3 years ago
What is the % yield when 12g of Mg react with HCl to produce 0.2g of H2?
goblinko [34]

Answer:

The yield is 20 %.

Explanation:

Mg + 2 HCl → MgCl2 + H2

(12 g Mg) / (24.30506 g Mg/mol) x (1 mol H2 / 1 mol Mg) x (2.015894 g H2/mol) = 0.9953 g H2.

(0.2 g) / (0.9953 g) = 0.20 = 20% yield

5 0
3 years ago
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