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2 years ago

Holly wants to design a test to find out how fast her friend Jill can walk from one end of the playground to the other.

2 answers:

7 0

Answer: D

the answer can not be A because the type of shoes jill is wearing doesn’t have anything to do with her speed

The answer can not be B because dogs are not any part of this experiement

the answer can not be C because they are testing the speed of a person not a bike

Orlov [11]2 years ago

6 0

Answer:

Explanation:

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Which choice below represents a negative impact that chemistry has on society?

RSB [31]

Answer:It’s C on edge 2020

(Combustion of car engines producing pollutants in the air)

Explanation:

I got it right :))

5 0

2 years ago

How many electrons in the 4 and 5th shell?

patriot [66]

The fifth shell can hold up to 50 electrons and the forth shell can hold 8 electrons

8 0

2 years ago

Zinc metal (Zn) will react with aqueous hydrochloric acid (HCI aq) to produce aqueous zinc chloride (ZnCl2 aq) and hydrogen gas

Debora [2.8K]

Answer:

$5$

Explanation:

Here, we want to get the equation of the reaction between Hydrochloric acid and Zinc metal

Zinc metal displaces the hydrogen from hydrochloric acid to form zinc chloride

We have the equation of reaction as:

$2HCl_{(aq)}\text{ + Zn}_{(s)}\text{ }\rightarrow\text{ ZnCl}_{2(aq)}\text{ + H}_{2(g)}$

3 0

7 months ago

H2O and C6H12O6 are examples of ______

ruslelena [56]

Compounds. They both have more than one element in them

4 0

2 years ago

A hot air balloon can have a volume of 2950 cubic meters (2.95 ✕ 106 liters) and operate at temperatures up to 250°F (121°C). As

TiliK225 [7]

Answer:

2.64 × 10⁶ g

Explanation:

We can find the mass of air using the ideal gas equation.

$P.V=n.R.T=\frac{m}{M} .R.T$

where,

P is the pressure (P = 1.00 atm)

V is the volume (V = 2.95 × 10⁶ L)

n is the number of moles

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (121°C + 273 = 394 K)

m is the mass

M is the molar mass (28.09 g/mol)

$m=\frac{P.V.M}{R.T} =\frac{1.00atm \times 2.95 \times 10^{6} L \times 28.97g/mol}{(0.08206atm.L/mol.K) \times 394 K } =2.64 \times 10^{6} g$

7 0

2 years ago