Answer:
The mass of this piece of metal is 37.68g
Explanation:
<u>Step 1:</u> Given data
q = m*ΔT *Cp
⇒with m = mass of the substance
⇒with ΔT = change in temp = final temperature T2 - initial temperature T1
⇒with Cp = specific heat (Cpwater = 4.184J/g °C) (Cpmetam = 0.9J/ g °C)
<u>Step2 : </u>
For this situation : we get for q = m*ΔT *Cp
q(lost, metal) = q(gained, water)
- mass of metal(ΔT)(Cpmetal) = mass of water (ΔT) (Cpwater)
-m (30.6 -100) * 0.9 = 75g *( 30.6 - 23.1) * 4.184J / g °C
-m * (-69.4) * 0.9 = 75g * (7.5) * 4.184J / g °C
-m * (-69.4) *0.9 = 2353.5
-m = 2353.5 / (-69.4 *0.9) = -37.68
m = 37.68g
The mass of this piece of metal is 37.68g
