<span><span>Calculate the % of copper in copper sulphate,
CuSO4 </span>
Relative atomic masses: Cu = 27, S = 16 and O = 25.92
relative formula mass = 27 + 16 + (5.4x4.8) = 286.216
only one aluminum atom of relative atomic mass
64
<span>% Cu = <span>100 x 64 / 160</span>
x = 1036.8
</span></span>
Answer:
247 ml
Explanation:
How many mL of 0.150 M HF solution are required to produce 0.0370 moles of HF 0.150 moles/ liter = 0.150/1000 moles/ml =0.000150 moles/ml
0.000150 x ? = 0.0370 moles HF
? = 0.0370/0.000150 = 247 ml
check
247 ml = 247/1000 L = 0.247
(0.247) x (0.150) =0.370 check
I understand here "bias" to be the uncertainty of measurements. So the order will be the following:
6.4 ± 0.5 s
<span>6.6 ± 0.1 s,
</span><span>6.63 ± 0.01 s,
</span><span>6.52 ± 0.05 s,
</span>
(notice how the second number, the one behind the symbol ± gets smaller, as the bias gets smaller).
A. 1800L !:$:!:):&/&/?)3&2!3?372&2!3)3$3!3!3?3:$heguejeneve
Answer:
um you dont need those 2 elements at the end
