Answer: Option (d) is the correct answer.
Explanation:
As it is known that like dissolves like. So, water being a polar compound is able to dissolve only polar compounds.
Hence, a compound that is ionic or polar in nature will readily dissolve in water. Whereas non-polar compounds will be insoluble in water.
As 
is a non-polar compound. Hence, it is insoluble in water.
On the other hand, 
is a polar compound due to difference in electronegativity of chlorine and carbon atom there will be development of partial charges. Hence, there will be dipole-dipole forces existing between them.
Whereas 
is an ionic compound and it will readily dissociate into ions when dissolved in water. Also, there will be ion-dipole interactions between sodium and nitrate ions.
Hence, will readily dissolve in water.
Thus, we can conclude that the compounds correctly arranged in order of increasing solubility in water are < < .
Dalton's model of the atom (ESAAO) ...
Thomson's model of the atom (ESAAP) ...
Rutherford's model of the atom (ESAAQ) ...
Bohr's model of the atom (ESAAR) ...
IamSugarBee
Given the data from the question, the number of aluminum atoms in aluminum oxide, Al₂O₃ is 2 (Option B)
<h3>Composition of aluminum oxide, Al₂O₃</h3>
From the formula of the compound, Al₂O₃ we see that the compound is composed of
<h3>How to determine the number of aluminum atoms </h3>
- Formula of compound = Al₂O₃
- Number of oxygen atoms j= 3 × 1 = 3
- Number of aluminum atoms = 2 × 1 = 2
From the above, we can conclude that Al₂O₃ contains 2 atoms of aluminum.
Learn more about mass composition:
brainly.com/question/11617445
Explanation:
When iodine heptafluoride reacts rapidly with water to give a mixture of periodic acid and hydrofluoric acid. Reaction equation for the same is as follows.
As it is given that there are 
moles of iodine heptafluoride are present. Molar mass of 
is 259.9 g/mol. Molar mass of 
is 227.94 g/mol and molar mass of HF is 20.01 g/mol.
Now, according to the reaction equation M gives M 
.
Also, the volume is given as 795 ml or 0.795 L (as 1 mL = 0.001 L).
Hence, calculate the concentration of into the solution as follows.
Concentration = 
= 
= 
mol/L
or, = 0.047 M
Now, as 1 mol of produces 7 mol HF. So, 
M HF.
Therefore, concentration of HF will be calculated as follows.
Concentration of HF = 
= 0.33 M
Thus, we can conclude that concentration of periodic acid is 0.047 M and concentration of hydrofluoric acid is 0.33 M.
