Let W = width of package
Let H = height of package
Let L = length of package
The perimeter cab be one of the following:
P = 2(L + W), or
P = 2(L + H)
The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
2(L + 10) <= 108
L + 10 <= 54
L <= 44 in
When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in
To satisfy both of these conditions requires that L <= 39 in.
Answer: 39 inches
Answer:
A. True
Step-by-step explanation:
......................................................................................
<em>Answer:</em>
<h2>
<em>x=</em><em>6</em><em>√</em><em>2</em></h2>
<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em><em>.</em><em>.</em><em>.</em>
<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>
On a number line, v would be all the numbers to the left of -3 (for example, |-4|=4 which is greater than 3) and all the values to the right of positive 3. Since it can't equal 3, v=-3 and v=3 are not included on the number line.
Hello from MrBillDoesMath!
Answer:
72
Discussion:
Total Surface area = area of pyramid base + 4 ( area of triangular face)
In our case this becomes
4*4 + 4( (1/2) (4)(7) ) =
= 16 + (2)(4)(7)
= 16 + 56
= 72
which is the first choice.
Note: the area of a triangular face was computed using (1/2) b h, which in our case is
(1/2) (4) (7)
Thank you,
MrB
