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3 years ago

6

Asthma is a condition in which it can be very hard for a person to breathe in enough air. Would it also be difficult for someone

with asthma to exercise?

1 answer:

Karolina [17]3 years ago

8 0

Answer:

B, no, as long as the persons cells are getting different types of molecules from food he can still exercise.

Step-by-step explanation:

You might be interested in

Solve for x: 3-(2x-5)<-4(x+2)

trapecia [35]

3-(2x-5)=-4(x+2)

We simplify the equation to the form, which is simple to understand
3-(2x-5)=-4(x+2)

Remove unnecessary parentheses
3-2x+5=-4*(x+2)

Reorder the terms in parentheses
3-2x+5=+(-4x-8)

Remove unnecessary parentheses
+3-2x+5=-4x-8

We move all terms containing x to the left and all other terms to the right.
-2x+4x=-8-3-5

We simplify left and right side of the equation.
+2x=-16

We divide both sides of the equation by 2 to get x.
x=-8

6 0

3 years ago

Read 2 more answers

Help I need to know I only have 15 min <br> What does x equal in x/2=-5

SSSSS [86.1K]

Answer:

x= -10

Step-by-step explanation:

Brainliest please? :)

3 0

3 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

5% of x is 15.what is x?help me with this question and ignore the last post I posted?

fomenos

X should be 300
15/x= 0.05
x= 15/0.05= 300
x=300

7 0

3 years ago

Read 2 more answers

I need the answer please don’t scam with a link I need the answer

Marizza181 [45]

Answer:

the answer is B

Step-by-step explanation:

the inequality is say any number bigger or equal to -5

so -5, -4.5, -3 is the answer.

5 0

3 years ago