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maksim [4K]
2 years ago
5

PLZ HURRY!!! NEED ANSWERS FAST!!!!

Mathematics
2 answers:
Vladimir79 [104]2 years ago
7 0

I think it is the first one.

prohojiy [21]2 years ago
7 0
It's the first one, your welcome
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A hairdresser combined three bottles of shampoo into one bottle. The first bottle had 4.8 ounces of shampoo, the second bottle h
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about 20

Step-by-step explanation:

its kindergarden math

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3 years ago
The map below shows the location of 3 houses where you had to do lawn work today. Your truck gets 8 miles per gallon of gasoline
ryzh [129]

Answer:

4.18 dollars to drive 20 miles

Step-by-step explanation:

7 0
3 years ago
If the diagonal of the rectangle is 10.5 inches and the length of the rectangle is 7.25 inches, what is the width of the rectang
o-na [289]

Answer:3.75

Step-by-step explanation:

6 0
2 years ago
Crispy Clover, a popular vegetarian restaurant, introduced a new menu that has 20%, percent more dishes than the previous menu.
Elden [556K]

Correct answers are D + D(\frac{1}{5}) and 1.2D i.e. Options A & D

<u>Step-by-step explanation:</u>

Options for this questions are:

A)D+1/5D

B)D+20

C)D+20D

D)1.2D choose two answers.

We have , Crispy Clover, a popular vegetarian restaurant, introduced a new menu that has 20%, percent more dishes than the previous menu. The previous menu had D dishes.We need to find expressions could represent how many dishes Crispy Clover's new menu has . Let's find out:

Initially , Number of dishes are D . Then 20% more dishes are there in menu

⇒ \frac{D(20)}{100}

So , Total Number of Dishes are

⇒ D + \frac{20d}{100}

⇒ D + \frac{20d}{20(5)}

⇒ D + D(\frac{1}{5})

⇒ D + D(0.2)

⇒ 1.2D

Therefore, Correct answers are D + D(\frac{1}{5}) and 1.2D i.e. Options A & D .

4 0
3 years ago
A production process is checked periodically by a quality control inspector. the inspector selects simple random samples of 30 f
777dan777 [17]

Answer:

Population Mean = 2.0

Population Standard deviation = 0.03

Step-by-step explanation:

We are given that the inspector selects simple random samples of 30 finished products and computes the sample mean product weight.

Also, test results over a long period of time show that 5% of the values are over 2.1 pounds and 5% are under 1.9 pounds.

Now, mean of the population is given the average of two extreme boundaries because mean lies exactly in the middle of the distribution.

So,   Mean, \mu = \frac{1.9+2.1}{2} = 2.0

Therefore, mean for the population of products produced with this process is 2.

Since, we are given that 5% of the values are under 1.9 pounds so we will calculate the z score value corresponding to a probability of 5% i.e.

             z = -1.6449 {from z % table}

We know that z formula is given by ;  

                Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

              -1.6449 = \frac{1.9 - 2.0}{\frac{\sigma}{\sqrt{n} } }     ⇒  \frac{\sigma}{\sqrt{n} }  = \frac{-0.1}{-1.6449}  

                                           ⇒ \sigma = 0.0608 * \sqrt{30}  {as sample size is given 30}

                                           ⇒ \sigma = 0.03 .

Therefore, Standard deviation for the population of products produced with this process is 0.0333.

7 0
3 years ago
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