Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.
<h3>What is the hang time equation?</h3>
The hang-time of the ball for a player of jump h is given by:
The expression can be simplified as:
For a player that has a hang time of 0.9s, the jump is found as follows:
h = 3.24 feet.
For a player that has a hang time of 0.8s, the jump is found as follows:
h = 2.56 feet.
The difference is given by:
3.24 - 2.56 = 0.68 feet.
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Answer:
162 unit²
Step-by-step explanation:
Refer to attachment.
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A:1.23
E: note that 125= 5^3 thus, log_b (125) = log_b(5^3) we can now simplify using the rule log_b(a^c) = c • log_b (a) log_b (5^3) = 3 • log_b (5) since log_b (5) = 0.41, we know that 3 • log_b (5) = 3•0.41 = 1.23
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Answer:
Step-by-step explanation: