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2 years ago

Plz help fast (worth 15 pts) A prism and two nets are shown below:

2 answers:

8 0

Image of a right triangular prism and 2 nets. The triangle bases have base 4, height 3, and diagonal side 5. The length of the prism from the bases is 8.6. Net A has 3 rectangles in a row. The middle one has sides AC and CD. This middle one has triangle ABC on top and identical triangle below. Net B is the same except that the triangle base ABC is on top of the last rectangle which has sides AC and CD. Units are in inches.

Step-by-step explanation:

DiKsa [7]2 years ago

4 0

Answer:

This is worth more than 15

Step-by-step explanation:

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10.5125 rounded to the nearest cent plz help me ty <3

Phoenix [80]

Answer: your answer should be 10.5130

Step-by-step explanation:

5 0

2 years ago

Help me with #5 pleaseeeeeeeeeee

earnstyle [38]

Answer:

$\angle 1 = 45$ degrees

Step-by-step explanation:

Sum of 3 angles in a triangle is 180..

The angles given are:

7x + 12

So we sum to 180 and write:

$60+7x+12+\angle 1=180\\72+7x+\angle 1=180\\7x+\angle 1=108$

Also, straight angle is 180 degrees, thus Angle 1 and (14x + 9) angle is sum to 180, thus we can write:

$14x+9+\angle 1=180\\14x + \angle 1=171$

Or we can write this as:

$14x + \angle 1=171\\\angle 1 = 171 - 14x$

We substitute this expression for Angle 1 into 1st equation we got and solve for x first,

$7x+\angle 1 = 108\\7x+( 171 - 14x)=108\\-7x=-63\\x=9$

Since x = 9, the angle "14x + 9" would be:

14(9) + 9 = 135

Hence Angle 1 would be:

$\angle 1 + 14x + 9 = 180\\\angle 1 + 135 = 180\\\angle 1 = 45$

6 0

2 years ago

Refer to the photo :D

OlgaM077 [116]

well, we know the ceiling is 6+2/3 high, and Eduardo has 4+1/2 yards only, how much more does he need, well, is simply their difference, let's firstly convert the mixed fractions to improper fractions and then subtract.

$\stackrel{mixed}{6\frac{2}{3}}\implies \cfrac{6\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{20}{3}} ~\hfill \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{20}{3}-\cfrac{9}{2}\implies \stackrel{using ~~\stackrel{LCD}{6}}{\cfrac{(2\cdot 20)-(3\cdot 9)}{6}}\implies \cfrac{40-27}{6}\implies \cfrac{13}{6}\implies\blacktriangleright 2\frac{1}{6} \blacktriangleleft$

4 0

2 years ago

Find the volume of 22 ft

Scilla [17]

This question is incomplete. There is no way to get a volume from a single
length

7 0

3 years ago

Please answer the side questions and the "#justkeepswimming" thank you if you do!!

fenix001 [56]

#just keep swimming I don’t know what you mean

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3 years ago