Answer:
The area of a rectangle is 520 square inches. The length is 3 more than twice the width. The equation 520 = 2w2 + 3w can be used to find the length and width of the rectangle.
Step-by-step explanation:
1st statement:
l= 2w+3
A= l × w
520= w×(2w+3)
520= 2w²+ 3w
2nd statement:
length of fencing= w+2l
120= w+2l
l= 60-w/2
A= (60-w/2) × w
A= 60w- w²/2
Hence this statement is incorrect
3rd statement:
H= x
B= x-4
P= x-2
Accoriding to pythagoras theorem
H²=P²+B²
x²=(x-4)²+(x-2)²
x²= x²-8x+16 + x²-4x+4
0= x²-12x+20
Hence this statement is incorrect
4th statement:
two consecutive even numbers are given by n and n+2
So this statement is incorrect
Answer:
(-8) ^4
Step-by-step explanation:
The base is the number being multiplied
-8
The exponent is the number of times it is multiplied
4
(-8) ^4
Answer:
The second, third and fourth are parallel to the given equation
Step-by-step explanation:
In order to determine if the slopes are the same, put all of the equations in slope-intercept form: y = mx + b. In order for lines in this form to be parallel, the m values of each have to be the exact same number, in our case, 4. Equation 2 has a 4 in the m position, just like the given, so that one is easy. Equation 2 is parallel.
Let's solve the third equation for y:
12x - 3y = 6 so
-3y = -12x + 6 and
y = 4x - 2. Equation 3 is parallel since there is a 4 in the m position.
Let's solve the fourth equation for y:
-20x + 5y = 45 so
5y = 20x + 45 and
y = 4x + 9. Equation 4 is also parallel since there is a 4 in the m position.
To solve this problem you must apply the proccedure shown below:
1. You have that the number of innings are expressed as a mixed number in the exercise:

2. If you want to write it as a decimal, you can convert the fraction as a decimal by dividing the numerator by the denominator and then, you must add this to the whole number part:

The answer is: 102.67
Answer:
74 units squared
Step-by-step explanation:
we know that the area of a square or rectangle is A = L × w
so we should just separate the object into it's individual rectangles/squares, solve for their areas, then add them together.
so I'll start with the middle square its length is 8 and width is 8 too.
A = 8 × 8
A = 64
now we'll move on to the other small ones to the side.
the one on the right side it's length is 2 and width is 2.
A = 2 × 2
A = 4
and then the last one on the left, Length is 3, width is 2.
A = 2 × 3
A = 6
now we'll add up all of the areas to get the total area.
Total = 64 + 4 + 6
Total = 74 units squared