There is no P in here, you can't solve for P without a P, Or I just don't get the question.
If the discriminant(b^2-4ac) is rational, then the quadratic is rational.
~ThePirc
Given: In ΔDEF and ΔDGF, Side DF is common.
To prove congruent of the triangle, we must require the minimum three conditions; like two sides and one angle of one triangle should be equal to the other triangle. OR Three sides of one triangle should be equal to the other triangle. OR Two angles and one side of one triangle should be equal to the other triangle. etc.
As per given question, to prove congruent of given triangles by SAS property then we should have given two sides and one angle of one triangle should be equal to the other triangle as additional information.
Since, In ΔDEF and ΔDGF, Side DF is common. So, we should require only one side and one angle that should be equal to another triangle.
An example would be 1/3 as an exact answer and 0.33 as an approximate answer because 1/3 = 0.333..... - a recurring decimal where there are an infinite number of 3's. 0.33 would be correct to the nearest hundredth.
Radicals are exact answers :- like √2 , √5 . Approximate value for √2 is 1.414
Answer:
Step-by-step explanation:
If y=6 and z=3, then plug in the numbers given to the variables.
3/2 times 6, -3 + 5/3 times 3.
6= 6/1, so, you can do the same operation.
3/2 times 6/1. then subtract 3 from that.( you have to simplify them to make equal denominators)
5/3 times 3/1 then add that to your previous answer.
