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Jet001 [13]
2 years ago
12

Wich expression shows the product of 9 and a number?

Mathematics
1 answer:
Monica [59]2 years ago
5 0

Answer:

There are two and they both mean the same thing.

Step-by-step explanation:

1. 9 x (times) n

2. 9n

I hope this helps u! :D

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PLZZZZ HELPPPPPPP!!!!
Vladimir79 [104]

Answer: The height of the building is 50.75 feet.

Step-by-step explanation:

The ratio between the height of the object and the casted shadow must be equal for all the objects, as the angle at which the source if light impacts them is the same.

For the person, we know that it is 5.8ft tall, and the shadow is 3.2ft long.

The ratio will be: 5.8ft/3.2ft = 1.8125

Now, if H is the height of the building, and the shadow that the building casts is 28ft, we must have:

H/28ft = 1.8125

Now we can solve this for H.

H = 1.8125*28ft = 50.75 ft

Then the height of the building is 50.75 feet.

3 0
3 years ago
8.4 divided by unknown gives you 2.8 what is the unknown
Anna007 [38]

Answer:

3

Step-by-step explanation:

8.4 ÷ 3 = 2.8

(Hopefully this answers your question)

6 0
3 years ago
A LARGE PIZZA AT TONY'S PIZZERIA IS A CIRCLE WITH
AfilCa [17]
You already know what it is cuh
5 0
3 years ago
Read 2 more answers
Write the equation of a line in slope-intercept form with a slope of −13 and a y-intercept of 4 .
frosja888 [35]

Answer:

y = -13x + 4

Step-by-step explanation:

You want to put it in the form y = mx + b where m is the slope and b is the y-intercept (For example, in the equation y = 2x + 3 the slope is 2 and the y-intercept is 3)

Since the slope is -13, m = -13.

Since the y-intercept is 4, b = 4.

This means the equation is y = -13x + 4

6 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
Svetllana [295]
Vertex form is
y = a {(x - h)}^{2}  + k
where (h,k) is the vertex.
We can see that the vertex of the graph is at (2,0), and that the graph opens downwards, but does not look stretched at all.
Therefore,
a = -1
h = 2
k = 0
and our vertex form equation is
y =  -  {(x - 2)}^{2}  + 0
which is answer A
7 0
3 years ago
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