All categories

2 years ago

Why can you use the constant of proportionality with any representation?

Mathematics

1 answer:

pantera1 [17]2 years ago

3 0

Answer:

The number k is called the constant of proportionality. One important way of thinking about this constant k is that it tells us how much y increases by if we increase x by exactly 1. to express that y is directly proportional to x.

You might be interested in

Please help due in 10 minutes

Anit [1.1K]

3(4x - 4) - 7x, when simplified, is 5x - 12. So your answer would be A, or the first one.

4 0

3 years ago

Read 2 more answers

Which two integers is - 206 between?

Anna71 [15]

Answer:

Answer:

102.5, 103.5

Step-by-step explanation:

a+a+1=206

2a+1=206

2a=205

a=102.5

103.5

I think there is a bug here. They can't be whole numbers.

Step-by-step explanation:

7 0

3 years ago

Finish the sequence 36,25,14

ruslelena [56]

Answer:

36, 25, 14, 3

Step-by-step explanation:

subtract 11

3 0

2 years ago

Which of the following techniques can be used to separate a homogeneous mixture into its component parts?

Airida [17]

The answer is A. This is because heat, pressure, or differences in density are some methods used to separate homogeneous mixtures.

4 0

3 years ago

Read 2 more answers

Make a Matlab script to make row 2 of matrix A equal to first row of A multiplied by the negative of the first element of row 2

stira [4]

Answer:

$X=\begin{Bmatrix}2& 1 &10 \\-3 & 5 & 4\end{Bmatrix}$

Step-by-step explanation:

From the question we are told that

Matrix is given as $A=\begin{Bmatrix}2 & -1 & 10\\-3 & 8 & 4\end{Bmatrix}$

Generally let the change in matrix be given as X

$X_1_2 = 2*(-(-1)) + - 1 = 1X_2_2 = -3 * (-(-1))+ 8 = 5$

Matlab output

$A=[2 -1 10;-3 8 4]\\a=(A(1,1)*-A(1,2))+A(1,2)\\b=(A(2,1)*-A(1,2))+A(2,2)\\X=[A(1,1) a A(1,3); A(2,1) b A(2,3)]\\$

Generally the matrix that makes row 2 of matrix A equal to first row of A multiplied by the negative of the first element of row 2 plus the original row is

$X=\begin{Bmatrix}2& 1 &10 \\-3 & 5 & 4\end{Bmatrix}$

6 0

2 years ago