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3 years ago

Which graph represents the function below?

Mathematics

1 answer:

Nady [450]3 years ago

4 0

Answer=last one

Good luck

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Please solve these system of equations using elimination. Random answers or links will be reported.

Aleks [24]

Answer:

1. x = 13 , y = − 19

2.x=23/2,y=-7

3.x=31/3,y=-28/3

4.x=102/25,y=28/25

5.x=7/3,y=22/3

6.x=5/2,y=4

Step-by-step explanation:

I hope this helped!

4 0

3 years ago

Read 2 more answers

The product of two consecutive positive integers is 272. Find the greater integer.

katrin2010 [14]

let the integers be x,x+1(consecutive integers)

To find the value of x+1(greater)

(x+1)*x=272

x^2+1x=272

the greater value is 17

x=16

Answer:17

5 0

3 years ago

Find the range of the function

stiks02 [169]

B is the answer you are looking for.

7 0

3 years ago

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

4 0

3 years ago

A lamp post 15 feet high casts a shadow

miv72 [106K]

Here you go! I decided to write it down for you. Sorry for the bad handwriting! :)

8 0

3 years ago