All categories

3 years ago

If a line with a slope of 6 crosses the y-axis at (0,-4), what is the equation of the line?

Mathematics

2 answers:

aev [14]3 years ago

6 0

Answer:

y = 6x-4

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

We know the slope is 6 and the y intercept is -4

y = 6x + -4

y = 6x-4

saul85 [17]3 years ago

6 0

Slope-intercept form: y = mx + b (m = slope and b = y-intercept)

Slope (m) = 6

y-intercept (b) = -4

Put into its final form.

y = 6x - 4

Best of Luck!

You might be interested in

Delta pays Pete Rose $360 per day in the maintenance department at air port. Pete became I'll Monday and went home after 1/5 of

Brrunno [24]

Answer:

$72 earned on monday

Step-by-step explanation:

Delta pays Pete Rose $360 per day in the maintenance department at air port. Pete became I'll Monday and went home after 1/5 of a day

Delta works for only 1/5 of the day

To get the amount earn , multiply the work done by the rate

$\frac{1}{5} \cdot 360 =72$

So $72 earned on monday

6 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

4 years ago

Select all the roots of the following equation.

strojnjashka [21]

Answer:

5, -9

Step-by-step explanation:

(x - 5)(x + 9) = 0 These are factors, to get the roots, just set each one equal to zero

x - 5 = 0

x = 5

x + 9 = 0

x = -9

6 0

3 years ago

Read 2 more answers

Draw two different shapes with a perimeter of 16 units. What is the area of each shape?

Nadusha1986 [10]

Shape #1: A square.
Every side is 4 units long.
The perimeter is 16 units.
The area is 16 square units.

Shape #2: A rectangle.
The length is 7.9 units.
The width is 0.1 unit.
The perimeter is 16 units.
The area is 0.79 of a square unit.

Shape #3: A circle.
The diameter is (16/π) units. (about 5.093 units)
The perimeter (circumference) is 16 units.
The area is (64/π) square units. (about 20.37 square units)

8 0

3 years ago

Read 2 more answers

Which statement is true?

Lera25 [3.4K]

Answer:

C is true as 2 pionts = a line

Step-by-step explanation:

I'm smartest in my class

6 0

2 years ago