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irakobra [83]
2 years ago
8

Solve for x

{11}{x+5}" align="absmiddle" class="latex-formula"> =3
Mathematics
2 answers:
Vika [28.1K]2 years ago
8 0
The answer is X = -4/3
DENIUS [597]2 years ago
8 0
The answer is x= -4/3
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You have 24 feet of fencing that you are using to make a rectangular dog pen. You want the dog pen to enclose 150 square feet. I
melamori03 [73]

Answer:

Not possible

Step-by-step explanation:

Given that

The area of the pen is 150 ft²

Assuming that the length of the pen is x, then the breadth of the pen will be 24 - x

Area = length * breadth

Area = x (24 - x)

Area = 24x - x²

24x - x² = 150

x² - 24x + 150 = 0

Using general quadratic formula, we have

[-b ± √(b² - 4ac)]/ 2a

Where

a = 1

b = -24

c = 150

On solving the equation, we get a number in the complex form of "i", and not a real number. As such, it's not possible for the 24 feet to enclose the area

7 0
3 years ago
A stick is x meter long. A string is 4 times as long as the stick. Express the length of the stick in terms of x.
soldier1979 [14.2K]
To represent the length of the string, we can use the variable y. 

y=4x

Y is four times longer than X. 

Hope this helps!
7 0
3 years ago
Data from the article "The Osteological Paradox: Problems inferring Prehistoric Health from Skeletal Samples" (Current Anthropol
iris [78.8K]

Answer:

(a) P (X < 109.78) = 0.9484.

(b) P (X < 109.78) = 0.9484.

(c) P (97 < X < 106) = 0.5328.

(d) P (X < 85.6 or X > 111.4) = 0.0369.

(e) P (X > 103) = 0.3085.

(f) P (X < 98.2) = 0.3821.

(g) P (100 < X < 124) = 0.5000.

(h) The middle 80% of all heights of 5 year old children fall between 92.31 and 107.70.

Step-by-step explanation:

It is provided that <em>X</em> follows a Normal distribution with mean, <em>μ</em> = 100 and standard deviation, <em>σ</em> = 6.

(a)

Compute the value of P (X > 89.2) as follows:

P (X>89.2)=P(\frac{X-\mu}{\sigma}>\frac{89.2-100}{6})\\=P(Z>-1.80)\\=P(Z

Thus, the value of P (X > 89.2) is 0.9641.

(b)

Compute the value of P (X < 109.78) as follows:

P (X

Thus, the value of P (X < 109.78) is 0.9484.

(c)

Compute the value of P (97 < X < 106) as follows;

P (97 < X < 106) = P (X < 106) - P (X < 97)

                          =P(\frac{X-\mu}{\sigma}

Thus, the value of P (97 < X < 106) is 0.5328.

(d)

Compute the value of P (X < 85.6 or X > 111.4) as follows;

P (X < 85.6 or X > 111.4) = P (X < 85.6) + P (X > 111.4)

                                       =P(\frac{X-\mu}{\sigma}\frac{111.4-100}{6})\\=P(Z1.9)\\=0.0082+0.0287\\=0.0369

Thus, the value of P (X < 85.6 or X > 111.4) is 0.0369.

(e)

Compute the value of P (X > 103) as follows:

P (X>103)=P(\frac{X-\mu}{\sigma}>\frac{103-100}{6})\\=P(Z>0.50)\\=14-P(Z

Thus, the value of P (X > 103) is 0.3085.

(f)

Compute the value of P (X < 98.2) as follows:

P (X

Thus, the value of P (X < 98.2) is 0.3821.

(g)

Compute the value of P (100 < X < 124) as follows;

P (100< X < 124) = P (X < 124) - P (X < 100)

                          =P(\frac{X-\mu}{\sigma}

Thus, the value of P (100 < X < 124) is 0.5000.

(h)

Compute the value of <em>x</em>₁ and <em>x</em>₂ as follows if P (<em>x</em>₁ < X < <em>x</em>₂) = 0.80 as follows:

P(X_{1}

The value of <em>z</em> is ± 1.282.

The value of <em>x</em>₁ and <em>x</em>₂ are:

-z=\frac{x_{1}-\mu}{\sigma} \\-1.282=\frac{x_{1}-100}{6}\\x_{1}=100-(6\times1.282)\\=92.308\\\approx92.31       z=\frac{x_{2}-\mu}{\sigma} \\1.282=\frac{x_{2}-100}{6}\\x_{2}=100+(6\times1.282)\\=107.692\\\approx107.70

Thus, the middle 80% of all heights of 5 year old children fall between 92.31 and 107.70.

5 0
3 years ago
A. what mouse stands one 2 legs<br>b.what duck stands on 2 legs
kati45 [8]
Mickey mouse and donald duck
4 0
3 years ago
Read 2 more answers
Really need help with Dilations in the Coordinate Plane
zimovet [89]

Answer:

I'd say (x,y) --> (2x,2y)

Step-by-step explanation:

Please understand if I'm wrong because I couldn't enhance the image. The quality made it a bit hard for me to accurately tell.

Sorry if I'm wrong.

4 0
2 years ago
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