Question:
The cost of 12 kg sugar is $240 what will be the cost of 3 kg sugar.
Given:
- Cost of 12 kg sugar = $240
To find?
Answer :
<u>To find </u><u>c</u><u>o</u><u>s</u><u>t</u><u> </u><u>of</u><u> </u><u>3kg sugar first we have to find cost of 1 kg sugar</u><u>.</u>
- Cost of 1 kg sugar = Cost of total no. of sugar ÷Total sugar
- Cost of 1 kg sugar = $240/12
- Cost of 1 kg sugar = $20
<u>Now Let's find cost of 3 kg sugar</u>
Cost of 3kg sugar = total no of sugar ×Cost of 1 kg sugar
Cost of 3kg sugar = 3×$20
Cost of 3kg sugar = $60
Answer:
Dilate circle A by a scale factor of 3.
Step-by-step explanation:
Generally, similar figures have sides in the same ratio
3(5) = 15
When dilate A by factor 3, it will look exactly like B
I'm taking the liberty of editing your function <span>v = e5xey: It should be
</span>
<span>v = e^5x^ey, with " ^ " indicating exponentiation.
</span>
Did you mean e^(5x) or (e^5)x? I'll assume it's e^(5x).
The partial of v = e^(5x)e^y with respect to x is e^(5x)(5)*e^y, or 25x*e^y.
The partial of v = e^(5x)e^y with respect to y is e^(5x)e^y.
Answer:
The function is missing in the question. The function is 
The answer is 4930
Step-by-step explanation:
Unit cost of a car is given as
Cost will be minimum when
x = -(-544)/ 2 x 0.8
= 340
Therefore, minimum cost for unit car is
= 4930
Answer:
The range is from 147 to 153 orders per day
Step-by-step explanation:
orders varies by 2% means that orders can be LOWER THAN THE AVERAGE, or HIGHER THAN THE AVERAGE.
That is, by 2%.
First, we need to find the decimal of 2%, so
2/100 = 0.02
We multiply this with the average number of order, 150, to get the varying amount:
0.02 * 150 = 3
Thus, the range would be:
150 - 3 = 147
150 + 3 = 153
The range is from 147 to 153 orders per day
