Answeryes
Step-by-step explanation:
Answer: 16
Step-by-step explanation:
multiplying by negative exponents can be a little tricky. So (1/4x)^-2 becomes 16/x^2 = __/x^2 so the missing number is 16
\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
Answer:
3
Step-by-step explanation:
its 3 just trust me
Answer:
ASA postulate
Step-by-step explanation:
To prove two triangles are congruent, you need 3 congruent parts in one of the patterns ASA, AAS, SSS, or SAS. Place your pencil on one vertex of the triangle then trace the figure. As you come to each congruent part, write either A for angle or S for side depending on what the part is. After doing so, you will see the pattern A - S - A since a side is congruent between two angles.
