Question

What is the reduction half-reaction for the equation below?

Answer 1

Answer:

$MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O$

Explanation:

Hello there!

In this case, since redox reactions are characterized by the presence of a reduction reaction, whereby the oxidation of the element decreases, and an oxidation reaction whereby the oxidation of the element increases.

In such a way, for the given chemical equation, we can see Fe is increasing its oxidation state from 2+ to 3+, which means it is oxidized. On the flip side, Mn is being reduced from 7+ (MnO₄⁻) to 2+ and this, the reduction half-reaction is:

$MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O$

Whereas five electrons are carried.

Regards!