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Whitepunk [10]
3 years ago
13

Anyone know how to do this

Mathematics
1 answer:
Anton [14]3 years ago
3 0

let

(hypotenuse ) c = 10 in

(perpendicular) a = 8 in

(base) b =?

By using Pythagoras theorem

c^2= a^2+b^2

(10)^2 = (8)^2 +(b)^2

100 = 64 +(b)^2

100- 64 = (b)^2

36 = (b)^2

√36 = b

6 = b

hence b= 6 in

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