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Whitepunk [10]
3 years ago
13

Anyone know how to do this

Mathematics
1 answer:
Anton [14]3 years ago
3 0

let

(hypotenuse ) c = 10 in

(perpendicular) a = 8 in

(base) b =?

By using Pythagoras theorem

c^2= a^2+b^2

(10)^2 = (8)^2 +(b)^2

100 = 64 +(b)^2

100- 64 = (b)^2

36 = (b)^2

√36 = b

6 = b

hence b= 6 in

You might be interested in
The phythatagorean Theron in two and three dimensions
natta225 [31]

The Pythagorean theorem states that a^2 + b^2 = c^2, where a and b are sides not opposite to the right angle, shown as a square. C represents the hypotenuse, or side opposite of the right angle

We see that a = 14 (it can also be b; both can be plugged in as both are  adjacent and not opposite of the right angle)

c = 19; hypotenuse is opposite of right angle

14^2 + b^2 = 19^2

196 + b^2 = 361

b^2 = 361 - 196

b^2 = 165

b = square root of 165

b = 12.845

x = 12.845

3 0
3 years ago
V(-4,4),down 6 units
Gnesinka [82]

Answer:

what ever letter (-4,-2)

7 0
4 years ago
Read 2 more answers
This graph shows the value of Jessica's vehicle at different years after she purchased it.
Olenka [21]

Answer:

B

it goes down by $16,000 in that time frame

3 0
3 years ago
A stereo manufacturer makes three types of stereo systems, I, II, and III, with profits of $20, $30, and $40, respectively. No m
romanna [79]
So,

1. Type I profits $20
2. Type II profits $30
3. Type III profits $40
4. I/day < 100
5. Type I needs 5 hrs.
6. Type II needs 10 hrs.
7. Type III needs 15 hrs.
8. Total hrs. available: 2000 hrs.

Every +5 hrs. spent yields an extra $10.
If we use 500 hrs. to make 100 Type I stereos, we will profit $2000.
If we use 500 hrs. to make 50 Type II stereos, we will profit $1500.
If we use 495 hrs. to make 33 Type III stereos, we will profit $1320.

We should use the first 500 hrs. to make Type I stereos.
We should use the last 1500 hrs. to make Type II stereos.

$2000 + $4500 = x
$6500 = x

There must be 100 Type I stereos made along with 150 Type II stereos made.
4 0
4 years ago
Sung drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 10 hours. When Sung drove
liraira [26]
Sung drove to the mountains

s₁=speed  when Sung drove to the mountains.
t=10 hour.
d=distance.

s₁=d/t
s₁=d/10 hour  ⇒s₁=d/10    (1)

Sung drove home:
s₂=speed when Sung drove home.
t=7 hour

s₂=s₁+18 miles/hour
s₂=d/7 hour    ⇒s₁+18 miles/h=d/7 hour ⇒ s₁+18=d/7  (2)

Whit the equations (1) and (2) make a system of equations:
s₁=d/10
s₁+18=d/7

we can solve this system of equations by substitution method.
d/10+18=d/7
least common multiple=70
7d+1260=10d
7d-10d=-1260
-3d=-1260
d=-1260/-3=420

Answer: distance= 420 miles.
7 0
4 years ago
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