Here is your answer
B. (12,30)
REASON:
Given,
.......(i)
.......(ii)
Putting the value of y from eq.i in eq.ii we get




Putting x=12 in eq.i we get



So,
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Hence answer is (12,30) in which x=12 and y=30
HOPE IT IS USEFUL
2 consecutive odd integers : x and x + 2
x(x + 2) = 27 + 6(x + x + 2)
x^2 + 2x = 27 + 6(2x + 2)
x^2 + 2x = 27 + 12x + 12
x^2 + 2x - 12x - 12 - 27 = 0
x^2 -10x - 39 = 0
(x + 3)(x - 13) = 0
x + 3 = 0
x = -3 (extraneous solution)
x - 13 = 0
x = 13
x + 2 = 15
so ur 2 integers are 13 and 15, with 15 being the largest
Sorry I don’t get that one
Answer:
The fourth one: Gavin has one and thirteen fourteenths buckets of water. Daven has one and three fourteenths buckets of water. Together they have three and two fourteenths buckets of water.
Step-by-step explanation:
Gavin = 1 13/14
Daven = 1 3/14
1 13/14 + 1 3/14 = 2 16/14
2 16/14 = 3 2/14 = three and two fourteenths
Answer:
$402
Step-by-step explanation:
Interest = principal x rate x time
I = 1500 x .268
I = $402