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Alinara [238K]
3 years ago
9

Help with khan academy problem, law of sines

Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

104°

Step-by-step explanation:

\frac{sin~B}{18} =\frac{sin~29}{9} \\sin~B=\frac{18}{9} \times sin~29\\sin~B=2~sin~29\\B=sin^{-1}(2 ~sin~29)\\=104^\circ

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Which factorization is equivalent to this expression?
grigory [225]

Answer:

10(3x+7)

Step-by-step explanation:

we have the expression:

30x + 70

To factor this expression we need to indentify the components that are common in both terms.

At first glance there is nothing in common, but we can notice that 30 and 70 are multiples of 10, that is:

10*3=30\\10*7=70

so we can substitute this into the expression:

10*3x+10*7

and now that we have the common term (the number 10) we can factorize it, that is, take out the common term and include a parentheses:

10(3x+7)

8 0
2 years ago
What is the probability that the second sock is black?
coldgirl [10]
I think it would be 5/8
5 0
2 years ago
Read 2 more answers
April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3
vlada-n [284]

Answer:

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = 5\frac{1}{4}\ hrs

5\frac{1}{4}\ hrs can be Rewritten as \frac{21}{4}\ hrs

Number of Hours Carl worked on Math project = \frac{21}{4}\ hrs

Number of Hours Sonia worked on Math project = 6\frac{1}{2}\ hrs

6\frac{1}{2}\ hrs can be rewritten as \frac{13}{2}\ hrs

Number of Hours Sonia worked on Math project = \frac{13}{2}\ hrs

Number of Hours Tony worked on Math project = 5\frac{2}{3}\ hrs

5\frac{2}{3}\ hrs can be rewritten as \frac{17}{3}\ hrs.

Number of Hours Tony worked on Math project = \frac{17}{3}\ hrs.

Now Given:

April worked 1\frac{1}{2} times as long on her math project as did Carl.

1\frac{1}{2}  can be Rewritten as \frac{3}{2}

Number of Hours April worked on math project = \frac{3}{2} \times Number of Hours Carl worked on Math project

Number of Hours April worked on math project = \frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs

Also Given:

Debbie worked 1\frac{1}{4} times as long as Sonia.

1\frac{1}{4}  can be Rewritten as \frac{5}{4}.

Number of Hours Debbie worked on math project = \frac{5}{4} \times Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = \frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs

Also Given:

Richard worked 1\frac{3}{8} times as long as tony.

1\frac{3}{8} can be Rewritten as \frac{11}{8}

Number of Hours Richard worked on math project = \frac{11}{8} \times Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = \frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs

Hence We will match each student with number of hours she worked.

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

5 0
3 years ago
Read 2 more answers
Given s(x) = 2x - 3 and t(x) = 5x + 4. Find the formula and domain for v(x) = s (x) / t (x) and w(x) = t (x) / s (x)
Liula [17]
V(x) = (2x - 3)/(5x + 4)
The domain is all Real numbers except x = -4/5, because if x = -4/5 the denominator would be zero and you cannot divide by zero.
{x | x ∈ R, x ≠ -4/5}

w(x) = (5x + 4)/(2x - 3)
similarly, x ≠ 3/2
so, {x| x ∈ R, x ≠ 3/2}
8 0
3 years ago
Read 2 more answers
Please help with this
Aleksandr-060686 [28]

Answer:

A

Step-by-step explanation:

(3x -14) + 9x is 90 degrees, so if you add 90 it becomes 180 degrees

It is 90 degrees because you can see that there is a right angle there

6 0
3 years ago
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