Explanation:
Formula to calculate specific rotation is as follows.
Specific rotation (![[\alpha]](https://tex.z-dn.net/?f=%5B%5Calpha%5D)
) = 
where, 
= observed rotation
c = concentration in g/ml
l = path length in dm
It is given that,
c = 
= 0.02 g/ml
l = 20 cm = 2 dm (as 1 dm = 10 cm)
Therefore, calculate the specific rotation as follows.
Specific rotation () =
= 
= 
Thus, we can conclude that the specific rotation of this compound is .
Answer:
Wouldn't the Earth's atmosphere be moving too fast that it eventually breaks out?
Explanation:
Do NOT trust me.
Answer:
Explanation:
For a general equilibrium
aA +bB ⇔ cC + dD ,
the equilibrium constant is K = [C]^c [D]^d / [A]^a[B]^b.
Our reasoning here should be based on the fact that Q has the same expression as K, but is used when the system is not at equilibrium, and the system will react to make Q = K to attain it ( Le Chatelier´s principle ).
So with this in mind, lets answer this question.
1. False: Q can large or small but is not the value of the equilibrium constant, it will predict the side towards the equilibrium will shift to attain it.
2. False: Given the expression for the equilibrium constant, we know if K is small the concentrations of the reactants will be large compared to the equilibrium concentrations of the products.
3. False: when the value of K is large, the equilibrium concentrations of the products will be large and it will lie on the product side.
4. True: From our previous reasongs this is the true one.
5. False: If K is small, the equilibrium lies on the reactants side.
Its <span>234or238 hope dis helped</span>
