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soldi70 [24.7K]
3 years ago
14

An aqueous solution of Calcium Chloride reacts with an aqueous solution

Chemistry
1 answer:
Tems11 [23]3 years ago
7 0

Answer:

the products formed are : -

1. CaCO3 - Calcium Carbonate

2. NaCl - Sodium Chloride

Explanation:

Calcium chloride reacts with Sodium carbonate to form Calcium carbonate and Sodium chloride. this reaction is a double displacement reaction.

here's the balanced chemical equation for the above reaction : -

CaCl2 + Na2CO3 =》CaCO3 + 2 NaCl

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Aspirin (acetylsalicylic acid, C9H8O4) is a weak monoprotic acid. To determine its acid-dissociation constant, a student dissolv
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Answer:

1. 3.57\times 10^{-4}was the K_a value calculated by the student.

2. 5.93\times 10^{-4}was the K_b of ethylamine value calculated by the student.

Explanation:

1.

The pH value of Aspirin solution = 2.62

pH=-\log[H^+]

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HAs\rightleftharpoons As^-+H^+

initially

c       0    0

At equilibrium

(c-x)      x   x

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3.57\times 10^{-4}was the K_a value calculated by the student.

2.

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C_2H_5NH_2+H_2O\rightleftharpoons C_2H_5NH_3^{+}+OH^-

initially

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K_b=\frac{x\times x}{(c-x)}

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K_b=5.93\times 10^{-4}

5.93\times 10^{-4}was the K_b of ethylamine value calculated by the student.

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