Answer:
70 seconds
Step-by-step explanation:
Given that;
The initial velocity
of the bullet fired = 1120 ft/s
Initial height h = 8 feet
The expression to determine how many seconds it takes the bullet to hit the ground is:

Thus;
Replacing the value of
= 1120 and h = 0 (i.e. when h =0) in the above expression; we have:


= -16t² + 1120t + 8
mulitiply through by (-)
= 16t² -1120t - 8
Divide through by 8
= 2t² - 140t - 1
The above expression forms a quadratic equation.
where;
a = 2
b = -140
c = - 1
So, by using the quadratic formula
, we have:






= 70
Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds
Answer:
Not clear of the question
Step-by-step explanation:
Answer:
0 (zero)
Step-by-step explanation:

<span>Equation at the end of step 1 :</span><span><span> (((4•(y2))-5y)+(3y-(7•(y2))))-((2y2+6y)-5)
</span><span> Step 2 :</span></span><span>Equation at the end of step 2 :</span><span><span> (((4•(y2))-5y)+(3y-7y2))-(2y2+6y-5)
</span><span> Step 3 :</span></span><span>Equation at the end of step 3 :</span><span> ((22y2 - 5y) + (3y - 7y2)) - (2y2 + 6y - 5)
</span><span> Step 4 :</span><span> Step 5 :</span>Pulling out like terms :
<span> 5.1 </span> Pull out like factors :
<span> -5y2 - 8y + 5</span> = <span> -1 • (5y2 + 8y - 5)</span>
I hope tht help