All categories

2 years ago

How long is the missing segment ? What is the name of that segment ?

Mathematics

2 answers:

SpyIntel [72]2 years ago

8 0

The length is 3

The name is AC

aleksley [76]2 years ago

8 0

Answer:

Step-by-step explanation:

11-8 = 3 thats your answer

You might be interested in

Solve the equation by factoring: x^2-8x+15=0

blsea [12.9K]

Answer:

that is your solution

hope it helps

4 0

2 years ago

Car Rentals rents cars and trucks for $25 and $30 a

Sladkaya [172]

Answer:let x be the number of cars, and 7-x be the number of trucks.

25x + 30(7-x) = 195

25x + 210-30x = 195

5x = 15

x = 3

So, 3 cars were not rented. If 7 total vehicles were not rented, 7 - 3 cars = 4 Trucks

4 Trucks were not rented.

Step-by-step explanation:

7 0

2 years ago

The high school band learns 3 new songs every 2 weeks for the home football games. Write an

kirza4 [7]

Answer:

1.5w = s

Step-by-step explanation:

4 0

2 years ago

Type the correct answer in each box. Use numerals instead of words.

lubasha [3.4K]

Answer:

System A has 4 real solutions.

System B has 0 real solutions.

System C has 2 real solutions

Step-by-step explanation:

System A:

x^2 + y^2 = 17 eq(1)

y = -1/2x eq(2)

Putting value of y in eq(1)

x^2 +(-1/2x)^2 = 17

x^2 + 1/4x^2 = 17

5x^2/4 -17 =0

Using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a = 5/4, b =0 and c = -17

$x=\frac{-(0)\pm\sqrt{(0)^2-4(5/4)(-17)}}{2(5/4)}\\x=\frac{0\pm\sqrt{85}}{5/2}\\x=\frac{\pm\sqrt{85}}{5/2}\\x=\frac{\pm2\sqrt{85}}{5}$

Finding value of y:

y = -1/2x

$y=-1/2(\frac{\pm2\sqrt{85}}{5})$

$y=\frac{\pm\sqrt{85}}{5}$

System A has 4 real solutions.

System B

y = x^2 -7x + 10 eq(1)

y = -6x + 5 eq(2)

Putting value of y of eq(2) in eq(1)

-6x + 5 = x^2 -7x + 10

=> x^2 -7x +6x +10 -5 = 0

x^2 -x +5 = 0

Using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b =-1 and c =5

$x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(5)}}{2(1)}\\x=\frac{1\pm\sqrt{1-20}}{2}\\x=\frac{1\pm\sqrt{-19}}{2}\\x=\frac{1\pm\sqrt{19}i}{2}$

Finding value of y:

y = -6x + 5

y = -6(\frac{1\pm\sqrt{19}i}{2})+5

Since terms containing i are complex numbers, so System B has no real solutions.

System B has 0 real solutions.

System C

y = -2x^2 + 9 eq(1)

8x - y = -17 eq(2)

Putting value of y in eq(2)

8x - (-2x^2+9) = -17

8x +2x^2-9 +17 = 0

2x^2 + 8x + 8 = 0

2x^2 +4x + 4x + 8 = 0

2x (x+2) +4 (x+2) = 0

(x+2)(2x+4) =0

x+2 = 0 and 2x + 4 =0

x = -2 and 2x = -4

x =-2 and x = -2

So, x = -2

Now, finding value of y:

8x - y = -17

8(-2) - y = -17

-16 -y = -17

-y = -17 + 16

-y = -1

y = 1

So, x= -2 and y = 1

System C has 2 real solutions

4 0

2 years ago

Read 2 more answers

Complete the statement of each of these rules:

never [62]

Answer:

a) (+) × (?) = (+)

(?) = (+)

b) (-) × (+) = ?

? = (-)

c) (?) × (-) = ?

? is undefined

Step-by-step explanation:

a) (+) × (?) = (+)

From the given equation in the question, by dividing both side of the equation by (+), we have;

((+) × (?))/(+) = (+)/(+)

(?) = (+)/(+) = (+)

Therefore, we have;

(+) × (+) = (+)

(?) = (+)

b) (-) × (+) = ?

From the given equation in the question we apply the operation rules as follows;

(-) × (-) = (+)

(-) × (+) = (-)

Therefore;

(-) × (+) = ? = (-)

? = (-)

c) (?) × (-) = ?

From the rules of multiplication, we have;

(-) × (-) = (+)

(+) × (-) = (-)

Therefore, when (?) = (-), ? = +, from which we have;

(?) ≠ ?, which is an error

Similarly, when (?) = (+), ? = -, therefore, (?) and ?, always changes sign

Therefore, the equation, (?) × (-) = ?, is undefined.

3 0

2 years ago