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3 years ago

How long is the missing segment ? What is the name of that segment ?

Mathematics

2 answers:

SpyIntel [72]3 years ago

8 0

The length is 3

The name is AC

aleksley [76]3 years ago

8 0

Answer:

Step-by-step explanation:

11-8 = 3 thats your answer

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Can someone help me

algol [13]

Answer:

A)310.18g/mol

B)84.9947g/mol

C)108.01 g/mol

d)159.7g /mole(Approx)

e)Coc12 g/mol

f) A1(OH)3 g/mol

g)83.9949 g/mol

h)197.9 g/mol

i)18.01529 g/mol

Step-by-step explanation:

Hope u happy with my answer...

please mark me as brainlest

7 0

3 years ago

In the equation -y = 10x, what is the unit rate

Andrews [41]

The unit rate<span> is a comparison of two different quantities when they are combined together</span>

4 0

3 years ago

The chair of the operations management department at Quality University wants to construct a p-chart for determining whether the

sasho [114]

Answer:

Prof B and Prof D

Step-by-step explanation:

From the question we are told that

Sample size 100

Instructor Number of Failures

Prof. A 13

Prof. B 0

Prof. C 11

Prof. D 16

Confidence level= 0.95

From Z table

Z=1.96

Generally proportion for failure is mathematically given as

$Proportion\ of\ Failure\ P=\frac{Number\ of\ Failure\ N}{Sample\ size\ S}$

$P=\frac{N}{S}$

For Prof A

$P_A=\frac{N_A}{S}$

$P_A=\frac{13}{100}$

$P_A=0.13$

For Prof B

$P_B=\frac{N_B}{S}$

$P_B=\frac{0}{100}$

$P_B=0$

For Prof C

$P_C=\frac{N_C}{S}$

$P_C=\frac{11}{100}$

$P_C=0.11$

For Prof D

$P_D=\frac{N_D}{S}$

$P_D=\frac{16}{100}$

$P_D=0.16$

Generally the average proportional failure is mathematically given as

$P_a_v_g=\frac{0.13+0+0.11+0.16}{4}$

$P_a_v_g=0.10$

Therefore having this we calculate for the control limits

Generally the upper control limit UCl is mathematically given as

Upper control limits:

$UCL =P_a_v_g +Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

$UCL =0.1 +1.96\sqrt{\frac{0.1(1-0.1) }{100}}$

$UCL =0.1 +1.96*0.03$

$UCL =0.1 +0.0588$

$UCL =0.1588$

Generally the upper control limit UCl is mathematically given as

Lower limit control limits:

$UCL =P_a_v_g _Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

$UCL =0.1 -1.96\sqrt{\frac{0.1(1-0.1) }{100}}$

$UCL =0.1 -1.96*0.03$

$UCL =0.1 -0.0588$

$UCL =0.0412$

Therefore the Range is 0.0412 to 0.1588

Given the range 0.0412 to 0.1588 Prof B and Prof D are outside the Range making them the correct options

4 0

3 years ago

HELPPPP...

uysha [10]

A. $6800 + $1360= $8160 total cost

b.
$68.85 each * 165 bracelets = $11360.25
$11360.25- $8160 total cost = $11278.75 profit

$11278.75 profit/$8160 total cost= 1.38218
1.38218= about 138%

Final answer: 138%
Warning: This answer will vary if you find the percent over cost (not including duty).

7 0

3 years ago

4x3 + x2 - 8x - 2 by grouping

WITCHER [35]

The answer is 2(3x-1)

8 0

3 years ago