Answer:
r = (3V/π)^1/3
Step-by-step explanation:
Given that :
Volume of a sphere = V = 4/3πr³
Dividing into 4
4/3 * 1/4 πr³ = 4/12πr³ = 1/3πr³
V = 1/3πr³
Cross multiply
3V = πr³
Divide both sides by π
3V/ π = πr³/ π
3V/ π = r³
Take the cube root of both sides
r = (3V/π)^1/3
The Median of the density is -6.
An illustration of a numerical distribution with continuous results is a density curve. A density curve is, in other words, the graph of a continuous distribution. This implies that density curves can represent continuous quantities like time and weight rather than discrete events like rolling a die (which would be discrete). As seen by the bell-shaped "normal distribution," density curves either lie above or on a horizontal line (one of the most common density curves).
It is clearly visible from the uniform density curve given in the question that the median of the population density is -6.
Because the area to the left and right of the density curve is the same.
Hence, the Median of density is -6.
Learn more about density curves here-
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Answer:
1-1/3 if its 14
1/52 if its 1/4
Step-by-step explanation:
Yes, I will list acute first (<90) and obtuse second (>90) and they need to add to 180
10 and 170
20 and 160
30 and 150
40 and 140
50 and 130
60 and 120
70 and 110
80 and 100 and so on
The correct answer is: [B]: "40 yd² " .
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First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
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→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
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Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
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Now, we add the areas of BOTH the triangle AND the square:
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→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
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