Answer:
750 mm, 7.5 cm
Step-by-step explanation:
Verify each case
case a) 2.5 km, 2,500 m
we know that
1 km ------> 1.000 m
so
2.5 km=2,500 m
therefore
The pair of measurements is equivalent
case b) 750 mm, 7.5 cm
we know that
1 cm ------> 10 mm m
so
7.5 cm=75 mm
therefore
<u>The pair of measurements is not equivalent</u>
case c) 3 m, 3,000 mm
we know that
1 m ------> 1.000 mm
so
3 m=3,000 mm
therefore
The pair of measurements is equivalent
case d) 120 cm, 1.2 m
we know that
1 m ------> 100 cm
so
1.2 m=120 cm
therefore
The pair of measurements is equivalent
Answer:
10
Step-by-step explanation:
Answer:
The option is D
![(n+4)^{2} - n^{2} = 8(n + 2)](https://tex.z-dn.net/?f=%28n%2B4%29%5E%7B2%7D%20-%20n%5E%7B2%7D%20%3D%208%28n%20%2B%202%29)
Step-by-step explanation:
Given
![(n+4)^{2} - n^{2} = 8(n + 2)](https://tex.z-dn.net/?f=%28n%2B4%29%5E%7B2%7D%20-%20n%5E%7B2%7D%20%3D%208%28n%20%2B%202%29)
put
we get
![(1+4)^{2}- 1^{2}= 8(1+2)\\5^{2}- 1^{2}= 8\times 3 = 24](https://tex.z-dn.net/?f=%281%2B4%29%5E%7B2%7D-%201%5E%7B2%7D%3D%208%281%2B2%29%5C%5C5%5E%7B2%7D-%201%5E%7B2%7D%3D%208%5Ctimes%203%20%3D%2024)
Similarly,
put
we get
![(2+4)^{2}- 2^{2} = 8(2+2)\\6^{2}- 2^{2}= 8\times 4 = 32](https://tex.z-dn.net/?f=%282%2B4%29%5E%7B2%7D-%202%5E%7B2%7D%20%3D%208%282%2B2%29%5C%5C6%5E%7B2%7D-%202%5E%7B2%7D%3D%208%5Ctimes%204%20%3D%2032)
put
we get
![(4+4)^{2}- 4^{2} = 8(4+2)\\8^{2}- 4^{2} = 8\times 6 = 48](https://tex.z-dn.net/?f=%284%2B4%29%5E%7B2%7D-%204%5E%7B2%7D%20%3D%208%284%2B2%29%5C%5C8%5E%7B2%7D-%204%5E%7B2%7D%20%3D%208%5Ctimes%206%20%3D%2048)
Answer:
Step-by-step explanation: