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aleksandrvk [35]
3 years ago
11

Follow the directions to solve the system of equations by elimination.

Mathematics
1 answer:
Ber [7]3 years ago
5 0
8x + 7y = 39
4x - 14y = -68

(multiply each term in second equation by -2)

8x + 7y = 39
-8x + 28y = 136

(add both equations)

35y = 175

(divide both sides by 35)

y = 5

(substitute value of y in one of the equations)

8x + 7(5) = 39
8x + 35 = 39
8x = 4
x = 1/2
(x, y) = (1/2, 5)
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Alexeev081 [22]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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Can someone write down the answers pls!!!!!!!!!!
snow_lady [41]

Step-by-step explanation:

6b x>=1

6c y>7

7a x>3

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7 0
3 years ago
To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

kx^2-5

so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

16k-5=-12+k

16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
Haley's age is 6 years less than half her mother's
Mrrafil [7]
Answer:
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Hope this helps
4 0
4 years ago
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Fantom [35]
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3C2/5C2 = 3/10
Having drawn two votes for candidate a on the first two draws, there are 2 votes for candidate b and one vote for candidate a remaining. The probability that a vote for candidate b will be drawn on the third draw is:
2/3.
After the first three draws, there reains one vote for candidate a and one vote for candidate b. The probability that a vote for candidate a will be drawn on the fourth draw is:
1/2.
The probability of the ordering aabab is therefore given by:
\frac{3}{10}\times\frac{2}{3}\times\frac{1}{2}=\frac{6}{60}
The answer is: 0.1.
7 0
3 years ago
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