4 years ago

Can someone help me please, thanks.

Mathematics

1 answer:

Travka [436]4 years ago

6 0

She forgot to convert hrs to minutes, A.

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PLEASE HELP!!!!!!!!!!AND READ ALL PLEASE

Scrat [10]

It terminates <span>9÷16=<span>.5625</span></span>

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3 years ago

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The average of p, q, and r is 40. The average of a, b, c, and d is 5. What is the average of a, b, c, d, p, q, and r?

Pachacha [2.7K]

Answer:

Step-by-step explanation:

Average = sum of numbers divided by number of numbers

sum of p q and r: 40*3=120

sum of a b c and d: 5*4=20

sum of a b c d p q r: 120+20=140

average of a b c d p q r: 140/7, or 20

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3 years ago

A game of chance involves rolling an unevenly balanced 4-sided die. The probability that a roll comes up 1 is 0.22, the probabil

GuDViN [60]

Answer:

Expected Winnings = 2.6

Step-by-step explanation:

Since the probability of rolling a 1 is 0.22 and the probability of rolling either a 1 or a 2 is 0.42, the probability of rolling only a 2 can be determined as:

$P_{1,2} = P_{1}+P_{2}\\P_{2} = 0.42 - 0.22 = 0.20$

The same logic can be applied to find the probability of rolling a 3

$P_{2,3} = P_{2}+P_{3}\\P_{3} = 0.54 - 0.20 = 0.34$

The sum of all probabilities must equal 1.00, so the probability of rolling a 4 is:

$P_{4} =1- P_{1}+P_{2}+P_{3} = 1-0.22+0.20+0.34\\P_{4}=0.24$

The expected winnings (EW) is found by adding the product of each value by its likelihood:

$EW=1*P_{1}+2*P_{2}+ 3*P_{3}+ 4*P_{4} \\EW=1*0.22+2*0.20+ 3*0.34+ 4*0.24\\EW=2.6$

Expected Winnings = 2.6

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3 years ago

Evaluate the expression 4!

kow [346]

Answer:

Step-by-step explanation:

Using the definition of factorial

n! = n(n - 1)(n - 2) ....... × 3 × 2 × 1, hence

4! = 4 × 3 × 2 × 1 = 24

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3 years ago

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Spaceship Earth is traveling around the sun at a speed of 18.5 miles per second. How far will we travel during a 52- minute math

Degger [83]

It will travel 57,720 miles.

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3 years ago

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