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antoniya [11.8K]
3 years ago
7

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics
2 answers:
Mashcka [7]3 years ago
7 0

Answer:

6.1 ⋅ 10^{3}

Step-by-step explanation:

i think smh

a_sh-v [17]3 years ago
7 0

Answer:

6100 because 3.05 times 10^7 is 30500000 and 5* 10 ^3 is 5000

30500000/5000 is 6100 or 6.1*10 ^3

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ou are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on cons
PolarNik [594]

Answer:

(\frac{4\sigma}{2.056})^2, rounded up, if needed, citizens should be included in the sample, in which \sigma is the standard deviation of the population.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.96}{2} = 0.02

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.02 = 0.98, so Z = 2.056.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Within 4 years of the actual mean

We have to find n for which M = 4. So

M = z\frac{\sigma}{\sqrt{n}}

4 = 2.056\frac{\sigma}{\sqrt{n}}

2.056\sqrt{n} = 4\sigma

\sqrt{n} = \frac{4\sigma}{2.056}

(\sqrt{n})^2 = (\frac{4\sigma}{2.056})^2

n = (\frac{4\sigma}{2.056})^2

(\frac{4\sigma}{2.056})^2, rounded up, if needed, citizens should be included in the sample, in which \sigma is the standard deviation of the population.

8 0
3 years ago
Find the measure of a supplement of a 20 3/4 degrees
ki77a [65]
20 \frac{3}{4}= \frac{83}{4} \\ \\ 180^{(4}-\frac{83}{4}= \frac{720-83}{4}=\boxed{\frac{637}{4}=159 \frac{1}{4}-the \ suplement}
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3 years ago
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Please answer quickly :’)
Virty [35]

check below for labels,

  • Full line is referred as diameter.

  • Half of diameter or from centre touching the circle is called radius.

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I should know this but I guess I don't, try going on x-actoschoolpro.com ;)
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Need help pls
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