3 years ago

Which expressions show the points Roopesh earns if 2 beanbags land in the hole Choose All that apply. And I mean all

Mathematics

1 answer:

aleksklad [387]3 years ago

7 0

B I think I’m not sure

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D/13>-3 A. D>-16 B. D>39 C. D>10 D. D>-39 Help?

mylen [45]

D/13>-3

You have to multiply 13 in both sides to eliminate the Denominator 13 on the left leaving variable D only.
(D/13)(13) > -3(13)

D > -39

so... D. D > -39

3 0

3 years ago

What is the nth term rule of the linear sequence below? 15 , 7 , − 1 , − 9 , − 17 , . . .

Doss [256]

You can see that you're constantly subtracting 8 to get the next number. So, we have

$a_1 = 15$

$a_2 = a_1-8$

$a_3 = a_2-8 = (a_1-8)-8=a_1-2\cdot 8$

$a_4=a_1-3\cdot 8$

$a_5=a_1-4\cdot 8$

So, as you can see, to get the n-th term we must subtract (n-1) times 8 from the original number.

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3 years ago

(a + 8)(b + 3) ab + 8a + 3b + 24 ab + 3a + 8b + 24 11ab 24ab

pochemuha

The answer is ab+3a+8b+24.

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3 years ago

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Write 10^4 as a product of the same factor

galina1969 [7]

Answer:

1000?

10x10x10x10?

don't really get it, but prob the second one.

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3 years ago

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Use the quadratic formula to solve for the roots of the following equation. x 2 – 4x + 13 = 0

Artyom0805 [142]

Quadratic Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , with a = x^2 coefficient, b = x coefficient, and c = constant

With our equation, plug in the values:

$x=\frac{4\pm \sqrt{(-4)^2-4*1*13}}{2*1}$

Next, solve the exponent and multiplications:

$x=\frac{4\pm \sqrt{16-52}}{2}$

Next, solve the subtraction:

$x=\frac{4\pm \sqrt{-36}}{2}$

Next, factor out i (i = √-1):

$x=\frac{4\pm \sqrt{36}i}{2}$

Next, solve the square root:

$x=\frac{4\pm 6i}{2}$

Lastly, divide and your answer is:

$x=2\pm 3i$

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3 years ago

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