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3 years ago

Given the triangle below what is the length of the third side rounded to the nearest whole number?

Mathematics

2 answers:

Len [333]3 years ago

8 0

Answer: given the diagram below, which of the following ordered pairs represents the vertex, A?

Alona [7]3 years ago

5 0

Not completely sure but i think it is 16

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3 years ago

I need help with this. How does one make 4 DIFFERENT equations for the SAME four points.

vichka [17]

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You put a equal sign or if its one equation then put a addition or subtraction sign etc.

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3 years ago

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Multiplicasion,que me da 32

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Answer: 4 por 8

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3 years ago

What is AE? Please help me

shepuryov [24]

The two triangles are similar, so will have a direct scale factor. We can find this by using the given measurements, 10÷8=1.25. So the scale factor from the smaller to the bigger triangle is 1.25. This means that 1.25×(x+6)=AE. We can solve this as we would with a regular linear equation:
1.25(x+6)=2x+6
1.25x+7.5=2x+6
1.5=0.75x
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∴ AE is 2x+6=10

4 0

3 years ago

What eigen value for this matix <br> (1 -2)<br> (-2 0)

natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

Compute the matrix $A' = A-\lambda I$ , where I is the identity matrix (1s on the diagonal, 0s elsewhere)
Compute the determinant of A'
Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

$A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]$

The determinant of this matrix is

$\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4$

Finally, we have

$\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}$

So, the two eigenvalues are

$\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}$

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2 years ago

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