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ioda
2 years ago
13

Need help with this question

Mathematics
2 answers:
larisa [96]2 years ago
7 0

Answer:I believe that it is the first one

Sveta_85 [38]2 years ago
3 0

Answer:

Compatible numbers

Step-by-step explanation:

Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. ... An estimate of 513 + 299 is found by mentally calculating 500 + 300 = 800.

You might be interested in
PLEASE PLEASE HELP !!
Virty [35]

Answer:

∠G = 23.3

∠H = 42.8

∠J = 19.9

Step-by-step explanation:

<em>Tan(G) = 0.43</em>

=> G = Tan⁻¹(0.43)

=> <u>∠G = 23.3</u>

<em>Sin(H) = 0.68</em>

=> H = Sin⁻¹(0.68)

=> <u>∠H = 42.8</u>

<em>Cos(J) = 0.94 </em>

=> J = Cos⁻¹(0.94)

=> <u>∠J = 19.9</u>

Hope this helps!

6 0
3 years ago
Evaluate: 29.04÷2.4−2.56
Crank

Answer:

9.54

Step-by-step explanation:

29.04/2.4 = 12.1

12.1-2.56 = 9.54

7 0
2 years ago
Read 2 more answers
In a village the number of houses and the number of flats are in the ration9:5 the number of flats and the number pf bungalows a
Dmitry_Shevchenko [17]

Answer: 180 houses

Step-by-step explanation:

From the question, we are informed that in a village the number of houses and the number of flats are in the ratio 9:5 while the number of flats and the number of bungalows are in the ratio 10:3 and that there are 30 bungalows in the village.

Since the ratio of the number of flats and the number of bungalows are in the ratio 10:3 and there are 30 bungalows in the village, the number of flats will be:

= 10/3 × 30

= 10 × 10

= 100 flats

Since we are told that the ratio of the number of houses to the number of flats are in the ratio 9:5 and we've gotten the number of flats as 100, then the number of houses will be:

= 9/5 × 100

= 9 × 20

= 180 houses

6 0
3 years ago
Plzz anyone solve all answers plzzzzzzzz​
algol13

You posted a lot of problems here. In the future please only post one problem at a time. Thank you.

I'll do the first two problems to get you started. Hopefully it will help you finish off the rest of the questions.

==========================================

Problem 1

{18, a, b, -3} is an arithmetic sequence or arithmetic progression (AP).

This means we have some number d added on to each term to get the next term.

first term = 18

second term = first term + d = 18+d = a

third term = second term + d = (18+d)+d = 18+2d = b

fourth term = third term + d = (18+2d)+d = 18+3d = -3

----

Let's solve that last equation for d

18+3d = -3

18+3d-18 = -3-18

3d = -21

3d/3 = -21/3

d = -7

----

The value d = -7 tells us to add -7 to each term to get the next term. In other words, we subtract 7 from each term to get the next term

first term = 18

second term = first term + d = 18+d = 18+(-7) = 18-7 = 11

third term = second term + d = 11+d = 11+(-7) = 11-7 = 4

fourth term = third term + d = 4+d = 4+(-7) = 4-7 = -3

----

We see that a = 11 and b = 4 are the second and third terms respectively.

Therefore, a+b = 11+4 = 15

-------------

<h3>Answer: 15</h3>

==========================================

Problem 2

A multiple of 4 is in the form 4*n for some integer n, ie n is a whole number.

We want to know which values of 4*n are between 10 and 250.

----

Divide both 10 and 250 by 4 to get the following

10/4 = 2.5

250/4 = 62.5

If n = 2, then 4*n = 4*2 = 8 is not between 10 and 250; however n = 3 will make 4*n = 4*3 = 12 to be between 10 and 250. We see that n = 3 is the smallest possible allowed value.

If n = 62, then 4*n = 4*62 = 248 is between 10 and 250; while n = 63 will make 4*n too big because 4*63 = 252. The largest n can get is n = 62

----

The question posed in question 2 is equivalent to asking the following: "How many values are in the set {3, 4, 5, ..., 60, 61, 62}?"

You could count all of the values in the set, but that exercise is very tedious busywork. There's a much faster way. First lets consider the set below

{a, a+1, a+2, ..., b-2, b-1, b}

where a,b are integers. Basically this set starts at 'a', counts up until we get to 'b'. The handy formula

c = b-a+1

will provide the exact count of values in the set {a, a+1, a+2, ..., b-2, b-1, b}

----

In this case, a = 3 and b = 62, making

c = b-a+1

c = 62-3+1

c = 60

There are 60 values in the set {3, 4, 5, ..., 60, 61, 62}

There are 60 multiples of four that are between 10 and 250.

-------------

<h3>Answer: 60</h3>
4 0
3 years ago
What is the relationship between ∠HIK and ∠JIK?
blagie [28]
Complementary angles --- they add up to 90 degrees
4 0
3 years ago
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