$a^{2} +b^{2} =c^{2} \\9^{2} + 13^{2} =c^{2}\\81+169=c^{2} \\250=c^{2} \\125=c$ $a^{2} +b^{2} =c^{2} \\16^{2} +18^{2} =c^{2} \\256+324=c^{2} \\580=c^{2} \\290=c$

3 4

$a^{2} +b^{2} =c^{2} \\19^{2} +14^{2} =c^{2} \\361+196=c^{2} \\557=c^{2} \\278.5=c$ $a^{2}+ b^{2}=c^{2} \\10^{2} +11^{2}=c^{2} \\100+121=c^{2} \\221=c^{2} \\110.5=c$

6 0

3 years ago

Can someone help? Thanks! :)

sukhopar [10]

Answer:

The second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )

Step-by-step explanation:

We can't confirm the length of these diagonals based on the appearance of the figure, so let us apply Pythagorean Theorem;

This diagonal divides each figure ( square + rectangle ) into two congruent, right angle triangles ⇒ from which we may apply Pythagorean Theorem, where the diagonal acts as the hypotenuse;

5^2 + 5^2 = x^2 ⇒ x is the length of the diagonal,

25 + 25 = x^2,

x^2 = 50,

x = √50

Now the same procedure can be applied to this other quadrilateral;

3^2 + 7^2 = x^2 ⇒ x is the length of the diagonal,

9 + 49 = x^2,

x^2 = 58,

x = √58

Therefore the second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )

5 0

3 years ago

Solve for p.

jeyben [28]

Answer: C

Step-by-step explanation:

thank me later

8 0

2 years ago