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3 years ago

Solve for x Enter the solutions from least to greatest . (x - 4)(- 5x + 1) = 0 lesser x = greater x =

Mathematics

1 answer:

nataly862011 [7]3 years ago

4 0

Lesser x is 1/2 or 0.3
greater x is 4

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Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

<em><u>Therefore, the two roots are:</u></em>

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago

Inverse square root (x+3)

QveST [7]

Answer:

The inverse function is f(x) = x^2 - 3

Step-by-step explanation:

To find the inverse of any function, start by switching the x and f(x) values.

f(x) = √(x + 3)

x = √(f(x) + 3)

Now solve for the new f(x). The result will be your inverse function.

x = √(f(x) + 3)

x^2 = f(x) + 3

x^2 - 3 = f(x)

8 0

3 years ago

Round 4.68 to the nearest tenth

irina1246 [14]

.60 is above 50 so you round up
4.60 becomes 5.00 if you round it to the nearest tenth

6 0

3 years ago

Read 2 more answers

Can u guys please help me with my math homework.

Sladkaya [172]

1.) circumference: 2(pi)r (use the pi sign) Area: pi(r^2)

2.) circumference: 2(pi)5=31.4
area: pi(5^2)=78.5

I’m not sure ab number 3 sorry :\

4 0

3 years ago

7. Isosceles triangle ABC is shown below with legs that measure 8 inches and a vertex angle of 50D. (a) Determine the area of AB

Flura [38]

Answer:

<h2>The area of the triangle ABC is 32 square inches.</h2>

Step-by-step explanation:

We know that the given triangle is a right-isosceles triangle, which means its leg are equal.

The area of a triangle is defined as

$A=\frac{1}{2}bh$

Where $b=8$ and $h=8$ . Replacing values, we have

$A=\frac{1}{2} \times 8 \times 8 = 32 \ in^{2}$

Therefore, the area of the triangle ABC is 32 square inches.

7 0

3 years ago