Use the substitution method

Mathematics

1 answer:

Nesterboy [21]3 years ago

3 0

Answer: x= -9 and y= -4

Hope it helps you

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Determine the first five iterates of f(x)=1.5x(1-x) for x0=0.8

kherson [118]

<span>f(x) = 1.5 x (1 - x)
f(0.8) = 1.5(0.8)(1 - 0.8) = 0.24
f(0.24) = 1.5(0.24)(1 - 0.24) ~= 0.274
f(0.274) = 1.5(0.274)(1 - 0.274) ~= 0.298
f(0.298) = 1.5(0.298)(1 - 0.298) ~= 0.314
f(0.314) = 1.5(0.314)(1 - 0.314) ~= 0.323

</span>So the answer is D : 0.24, 0.274, 0.298, 0.314, 0.323

3 0

3 years ago

Rationalize the denominator:<br><br> Please give step by step solution

MrMuchimi

Answer:

1 + i

Step-by-step explanation:

To rationalize multiply numerator and denominator by (2 + i )

$\frac{3+i}{2-i}= \frac{3+i}{2-i} \times \frac{2+i}{2+i} = \frac{(3+i)(2+i)}{(2-i)(2+i)} = \frac{6+3i+2i-1}{4-(-1)} = \frac{5+5i}{5} = 1 + i$

5 0

3 years ago

Divide: (5 + 4i) / (-3 – 2i)

Phantasy [73]

Answer:

Step-by-step explanation:

$\frac{5+4i}{-3-2i}\\\\\mathrm{Apply\:complex\:arithmetic\:rule}:\\\\\quad \frac{a+bi}{c+di}\:=\:\frac{\left(c-di\right)\left(a+bi\right)}{\left(c-di\right)\left(c+di\right)}\:=\:\frac{\left(ac+bd\right)+\left(bc-ad\right)i}{c^2+d^2}\\\\a=5,\:b=4,\:c=-3,\:d=-2\\\\=\frac{\left(5\left(-3\right)+4\left(-2\right)\right)+\left(4\left(-3\right)-5\left(-2\right)\right)i}{\left(-3\right)^2+\left(-2\right)^2}\\\\Refine\\=\frac{-23-2i}{13}\\\\$