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ICE Princess25 [194]

3 years ago

12

DESPERATE WILL GIVE BRAINLIST AND THANKS (PLZ HURRY)

1 answer:

Juli2301 [7.4K]3 years ago

8 0

Answer:

B

Explanation:

Its not litteral

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A freight train rolls along a track with considerable momentum. If it rolls at the same speed but has twice as much mass, its mo

GREYUIT [131]

Answer:

doubled

Explanation:

<u>Step 1</u>. Linear momentum (p) = mass X velocity = mv

p = mv -----equation 1

<u>Step 2</u>. if the mass is now twice and speed is same

p = (2*m)v -----equation 2

solving equation 1 and 2 together,

p = mv = 2mv

p = 2

Therefore, its momentum is doubled

7 0

3 years ago

When the mass is removed, the length of the cable is found to be l0 = 4.66 m. After the mass is added, the length is remeasured

zaharov [31]

Answer:

$\gamma=6.07*10^5\frac{N}{m^2}$

Explanation:

For a linear elastic material Young's modulus is a constant that is given by:

$\gamma=\frac{F/A}{\Delta L/L_0}$

Here, F is the force exerted on an object under tensio, A is the area of the cross-section perpendicular to the applied force, $\Delta L$ is the amount by which the length of the object changes and $L_0$ is the original length of the object. In this case the force is the weight of the mass:

$F=mg\\F=55kg(9.8\frac{m}{s^2})\\F=539N$

Replacing the given values in Young's modulus formula:

$\gamma=\frac{F/\pi r^2}{(L_1-L_0)/L_0}\\\gamma=\frac{539N/\pi(0.045m)^2}{(5.31m-4.66m)/4.66m}\\\gamma=6.07*10^5\frac{N}{m^2}$

6 0

3 years ago

How are sedimentary rock layers used by scientist to learn about the past

DiKsa [7]

They are used by scientist because of the texture and shapes.

5 0

3 years ago

Read 2 more answers

An airplane is at rest on a runway. It accelerates at 10 m/s2 for 15 seconds. How fast is it now traveling? Please show work eve

KonstantinChe [14]

Answer:

150

Explanation:

v = at

v = 10(15)

v = 150 m/s

6 0

3 years ago

Two pieces of clay are moving directly toward each other. When they collide, they stick together and move as one piece. One piec

aksik [14]

Answer:

0.961

Explanation:

m1 = 300 g = 0.3 kg

u1 = 1 m/s

m2 = 600 g = 0.6 kg

u2 = - 0.75 m/s

Let after collision they move together with velocity v.

By using the conservation of linear momentum

Total momentum before collision = Total momentum after collision

m1 x u1 + m2 x u2 = (m1 + m2) v

0.3 x 1 - 0.6 x 0.75 = (0.3 + 0.6) v

0.3 - 0.45 = 0.9 v

v = - 0.166 m/s

Total initial Kinetic energy

$K_{i}=0.5m_{1}u_{1}^{2}+0.5m_{1}u_{1}^{2}$

$K_{i}=0.5\times 0.3\times 1\times 1+0.5 \times 0.6 \times 0.75 \times 0.75$

$K_{i}=0.31875 J$

Total final Kinetic energy

$K_{f}=0.5\left ( m_{1}+m_{2} \right )v^{2}$

$K_{f}=0.5\times 0.9 \times 0.166 \times 0.166$

$K_{f}=0.0124 J$

fraction of kinetic energy lost

$\frac{K_{i}-K_{f}}{K_{f}}=\frac{0.31875-0.0124}{0.31875}=0.961$

7 0

3 years ago