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I am Lyosha [343]
3 years ago
7

How can a small boy balance a big boy on a sea saw?​

Physics
2 answers:
irina [24]3 years ago
7 0

Answer:

Answer: Say the big boy is 40kg and the small boy is 20kg... ... ...then by the rule that moments around a fulcrum or pivot should be equal for equilibrium, the distance of big boy from pivot=half of dist of small boy from pivot

Lina20 [59]3 years ago
7 0

Answer:

If the big boy weighs 30 kilograms and the small boy weighs 15 kilograms, the distance between the two boys must be equal for equilibrium, hence the big boy's distance from the pivot must be half of the small boy's distance. 

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A beaker of vegetable oil contains a beam of light that is aimed at a surface at an angle of 34 degrees as shown. If the index o
OverLord2011 [107]

Answer:

Angle of reflection of light is 34 degree

Explanation:

As per law of reflection of light we know that

angle of incidence of light = angle of reflection of light

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angle of incidence on the surface of oil is given as

\theta_i = 34 degree

so we know that

\theta_i = \theta_r

so here we can say that reflection angle of light will be same as angle of incidence

\theta_r = 34 degree

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3 years ago
Iron oxide reacts with aluminum to give aluminum oxide and iron. What kind of chemical reaction is this?
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a displacement reaction

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A sound wave has a frequency of 247 Hz and a wavelength of 1.4 m. What is the speed of the sound wave in air?
zavuch27 [327]
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5 0
3 years ago
A World-class sprinter can reach a top speed of about 11.5 m/s in the first 18.0 m of a race. What is the average acceleration o
irina [24]

Answer

a = 3.674 m / s ^ 2


t = 3.13 s

Using the kinematic equations for the movement we have:


h(t) = P_{0} + Vot + \frac{1}{2}at ^ 2 (1)


V_{f} = V_{0} + at (2)


Where:


P_{0} = initial position


V_{0}} = initial velocity


a = acceleration


t = time in seconds


V_{f} = final speed


We know:


P_{0}=0


V_{0}= 0

h = 18 m


V_{f} = 11.5\frac{m}{s}

  So:

 From (2) we have that: t =\frac{V_{f}}{a}


t =\frac{11.5}{a}

From (1) we have to:


h (t) = 0.5at ^ 2\\h = 18 = 0.5at ^ 2

Then we clear "a" to find the acceleration.


\frac{36}{t^2} = a\\a = \frac{36}{(\frac{11.5}{a})^2} \\\\a =\frac{11.5^2}{36}\\a = 3.674 m / s ^2

Then, the time it takes to reach this speed is:


t =\frac{V_{f}}{a}\\t =\frac{11.5}{3.674}\\t = 3.13 s

4 0
3 years ago
Read 2 more answers
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