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GalinKa [24]
2 years ago
15

1. What are the units of area under the line/curve? 2. Does the area have any meaning?

Physics
1 answer:
TiliK225 [7]2 years ago
6 0

The area under the velocity time graph is 125 m and the meaning of the area is displacement.

<h3>What is area under velocity - time graph?</h3>

The area under a velocity time graph represents the displacement of the object.

total area of the graph = A1 + A2

total area of the graph = ¹/₂ (base₁)(height₁) + ¹/₂ (base₂)(height₂)

total area of the graph = ¹/₂(4)(40) + ¹/₂(3)(30)

total area of the graph = 125 m

Thus, the area under the velocity time graph is 125 m and the meaning of the area is displacement.

Learn more about velocity time graph here: brainly.com/question/4710544

#SPJ1

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You have 2 objects flying towards you. One of them is havier with lower velocity and the other one is lighter but has higher vel
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3 years ago
Circle the letter of each expression that has four significant figures. A. 1.25 x 10^4 B. 12.51 C. 0.0125 D. 0.1255
Andreyy89

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letter B

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3 years ago
If the mass of a person is 600kg on Earth what is the persons mass on the moon
nika2105 [10]

Answer:

The mass of the person would remain 600kg.

Explanation:

mass refers to the amount of matter in a particular object. therefore even though the moon has less gravitational force than the Earths, it still would have the same mass since the person is made up of the same amount of matter on Earth and in the moon.

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3 0
3 years ago
In SI units, what is the magnitude the net force acting on a 1,152 kg car that accelerates uniformly along a straight line from
geniusboy [140]

Answer:

Fnet = 14515.2 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

Fnet = Fapp + Fg

Where;

  • Fnet is the net force.
  • Fapp is the applied force.
  • Fg is the force due to gravitation.

Given the following data;

Mass = 1,152 kg

Initial velocity, u = 3m/s

Final velocity, v = 17m/s

Time, t = 5 seconds

To find the magnitude of the net force;

First of all, we would determine the acceleration of the car.

Acceleration = (v-u)/t

Acceleration = (17 - 3)/5

Acceleration = 14/5

Acceleration = 2.8m/s

To find the applied force;

Fapp = mass * acceleration

Fapp = 1,152 * 2.8

Fapp = 3225.6 N

Next, we would find the force exerted on the car due to gravity.

Fg = mass * acceleration due to gravity

We know that acceleration due to gravity is equal to 9.8m/s²

Fg = 1152 * 9.8

Fg = 11289.6N

Substituting the values into the equation, we have;

Fnet = 3225.6 + 11289.6

Fnet = 14515.2 Newton

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