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2 years ago

Estimate the square root to the nearest integer.

Mathematics

1 answer:

nexus9112 [7]2 years ago

3 0

Answer:
3
Explanation:
3^2 is equal to 9, and 4^2 is equal to 16, so sqrt(10) must be in between 9 and 16. Since 10 is closer to 9 than to 16, sqrt(10) is closer to 3 than 4, which means that to the nearest integer sqrt(10)=3

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V= u + at u= 2 a = -5 t = 1 글 Work out the value of v.

Maksim231197 [3]

Answer:

v = - 3

Step-by-step explanation:

Given

v = u + at ← substitute u = 2, a = - 5, t = 1 into the expression

v = 2 + (- 5 × 1) = 2 + (- 5) = 2 - 5 = - 3

5 0

3 years ago

The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).21,42,84,...Find the 7th term.

Julli [10]

Answer:

21,42,84,168,336,672, 1,344

Step-by-step explanation:

The pattern is to multiply the previous term by 2 to find the next term. The seventh term should be 1,344.

4 0

3 years ago

Read 2 more answers

Consider the line y= -5/2x +6 what is the slope of the parallel line

zepelin [54]

Answer:

The equation is not linear so the slope does not exist. And neither does a slope for the parallel line.

Step-by-step explanation:

Good luck xx

4 0

2 years ago

Which of the followint iw a linear equation

SpyIntel [72]

Answer:

11.C

12.B

Step by step explanation:

4 0

3 years ago

What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?

Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

SOLUTION:

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)

We know that, distance between two points $P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right)$ is given by

$P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now,

$\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}$

8 0

2 years ago