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Luda [366]
2 years ago
12

Estimate the square root to the nearest integer.

Mathematics
1 answer:
nexus9112 [7]2 years ago
3 0
Answer:
3
Explanation:
3^2 is equal to 9, and 4^2 is equal to 16, so sqrt(10) must be in between 9 and 16. Since 10 is closer to 9 than to 16, sqrt(10) is closer to 3 than 4, which means that to the nearest integer sqrt(10)=3
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V= u + at<br> u= 2<br> a = -5<br> t = 1 글<br> Work out the value of v.
Maksim231197 [3]

Answer:

v = - 3

Step-by-step explanation:

Given

v = u + at ← substitute u = 2, a = - 5, t = 1 into the expression

v = 2 + (- 5 × 1) = 2 + (- 5) = 2 - 5 = - 3

5 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).21,42,84,...Find the 7th term.
Julli [10]

Answer:

21,42,84,168,336,672, 1,344

Step-by-step explanation:

The pattern is to multiply the previous term by 2 to find the next term. The seventh term should be 1,344.

4 0
3 years ago
Read 2 more answers
Consider the line y= -5/2x +6 what is the slope of the parallel line
zepelin [54]

Answer:

The equation is not linear so the slope does not exist. And neither does a slope for the parallel line.

Step-by-step explanation:

Good luck xx

4 0
2 years ago
Which of the followint iw a linear equation
SpyIntel [72]

Answer:

11.C

12.B

Step by step explanation:

4 0
3 years ago
What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?
Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

<u>SOLUTION: </u>

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)  

We know that, distance between two points P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right) is given by  

P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Now,  

\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}

8 0
2 years ago
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