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lara31 [8.8K]
1 year ago
9

What other information do you need to prove ΔABE is congruent to ΔEDA by SSS?

Mathematics
1 answer:
Stels [109]1 year ago
7 0

To prove ΔABE is congruent to ΔEDA by SSS we need that EAC should be an equilateral triangle.

What is an equilateral triangle?

A triangle is said to be equilateral if each of its three sides is the same length. In the well-known Euclidean geometry, an equilateral triangle is also equiangular, meaning that each of its three internal angles is 60 degrees and congruent with the others.

Here, we have

AEC is a triangle in which B∈ AC and D∈ EC

Such that,

∠ABE = 90°,

∠ADE = 90°,

Also, BC = CD

Now, we have to prove that :

Δ ABE is congruent to Δ EDA

Proof :

If EAC is an equilateral triangle,

By the property of an equilateral triangle,

EA = AC = EC

If AC = EC

AB + BC = ED + CD

AB + CD = ED + CD

AB = ED

Also, AE = AE ( common segment )

Now, if in two right triangles hypotenuse are equal and any corresponding legs are equal,

Then, the other legs must be equal,

That is, BE = DA,

Hence, by the SSS postulate of congruence,

Δ ABE ≅ Δ EDA

Hence, to prove ΔABE is congruent to ΔEDA by SSS we need that EAC should be an equilateral triangle.

To learn more about the equilateral triangle from the given link

brainly.com/question/15294703

#SPJ4

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I'll do the first one to get you started. The answer is -3

=================================================

Explanation:

When x = -1, y = 0 as shown in the first column. The second column says that (x,y) = (0,1) and the third column says (x,y) = (1,0)

We'll use these three points to determine the quadratic function that goes through them all.

The general template we'll use is y = ax^2 + bx + c

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Plug in (x,y) = (0,1). Simplify

y = ax^2 + bx + c

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Plug in (x,y) = (-1,0) and c = 1

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a = b-1

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Plug in (x,y) = (1,0), c = 1, and a = b-1

y = ax^2 + bx + c

0 = a(1)^2 + b(1) + 1 ... replace x with 1, y with 0, c with 1

0 = a + b + 1

0 = b-1 + b + 1 ... replace 'a' with b-1

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If b = 0, then 'a' is...

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In summary so far, we found: a = -1, b = 0, c = 1

Therefore, y = ax^2 + bx + c turns into y = -1x^2 + 0x + 1 which simplifies to y = -x^2 + 1

------------

The last thing to do is plug x = 2 into this equation and simplify

y = -x^2 + 1

y = -2^2 + 1

y = -4 + 1

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Natasha2012 [34]

Answer:

The symbols that we will use are:

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