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Maru [420]
3 years ago
11

If you multiply six positive numbers the product will be ______.if you multiply six negative numbers the product's sign will be_

______
Mathematics
2 answers:
Rzqust [24]3 years ago
5 0
The product will be positive
And the product will be positive
AnnZ [28]3 years ago
3 0
If u multiple six positive numbers the product is positive.

If you multiply six negative numbers the products sign will be positive
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Answer:

30. x=5\\y=5\sqrt{3}

31.  x=4\\y=4\sqrt{3}

32. x=6\\y=6\sqrt{3}

33. x=4.5\\y=\frac{9\sqrt{3} }{2}

34. x=40\\y=40\sqrt{3}

35. x=7.5\\y=\frac{15\sqrt{3} }{2}

Step-by-step explanation:

Use SOHCAHTOA to find one of the missing sides, then use the pythagorean theorem (x^{2}+ y^{2} =z^{2}) to find the other one

sin=\frac{opposite}{hypotenuse}

cos=\frac{adjacent}{hypotenuse}

tan=\frac{opposite}{adjacent}

30.

First find x using Sin

sin(30)=\frac{x}{10}

10*sin(30)=x

x=5

Then use the pythagorean theorem to find y

5^{2}+ y^{2} =10^{2}

25+y^{2} =100

y^{2} =75

\sqrt{y^{2}} =\sqrt{75}

y=5\sqrt{3}

32.

First use Sin to find x

sin(30)=\frac{x}{8}

8*sin(30)=x

x=4

Then use the pythagorean theorem to find y

4^{2}+ y^{2} =8^{2}

16+y^{2} =64

y^{2} =48

\sqrt{y^{2} } =\sqrt{48}

y=4\sqrt{3}

32.

First use Sin to find x

sin(30)=\frac{x}{12}

12*sin(30)=x

x=6

Then use the pythagorean theorem to find y

6^{2}+ y^{2} =12^{2}

36+y^{2} =144

y^{2} =108

\sqrt{y^{2} } =\sqrt{108}

y=6\sqrt{3}

33.

First use Sin to find x

sin(30)=\frac{x}{9}

9*sin(30)=x

x=4.5

Then use the pythagorean theorem to find y

4.5^{2}+ y^{2} =9^{2}

20.25+y^{2} =81

y^{2} =60.75

\sqrt{y^{2} } =\sqrt{60.75}

y=\frac{9\sqrt{3} }{2}

34.

First use Sin to find x

sin(30)=\frac{x}{80}

80*sin(30)=x

x=40

Then use the pythagorean theorem to find y

40^{2}+ y^{2} =80^{2}

1600+y^{2} =6400

y^{2} =4800

\sqrt{y^{2} } =\sqrt{4800}

y=40\sqrt{3}

35.

First use Sin to find x

sin(30)=\frac{x}{15}

15*sin(30)=x

x=7.5

Then use the pythagorean theorem to find y

7.5^{2}+ y^{2} =15^{2}

56.25+y^{2} =225

y^{2} =168.75

\sqrt{y^{2} }=\sqrt{168.75}

y=\frac{15\sqrt{3} }{2}

4 0
4 years ago
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