Question

Please help.. Solve for the area of the figure below and show work.

Answer 1

Answer and Step-by-step explanation:

1. We can see that this kite-shape has 4 triangles in it.

The area of a triangle is as follows:

$A = \frac{bh}{2}$

Where:

b = Base (length)

h = Height

Top Right Triangle Area:

b = 9

h = 3

A = $\frac{3 * 9}{2}$

A = $\frac{27}{2}$

Bottom Right Triangle Area:

b = 9

h = 3

A = $\frac{3 * 9}{2}$

A = $\frac{27}{2}$

Top Left Triangle Area:

b = 4

h = 3

$A = \frac{4*3}{2}$

A = $\frac{12}{2}$

A = 6

Bottom Left Triangle Area:

b = 4

h = 3

$A = \frac{4*3}{2}$

A = $\frac{12}{2}$

A = 6

Now, we add all the areas together to get the area of the kite figure.

A = $\frac{27}{2}$ +

A = 27 + 12

A = 39

The area of the kite figure is 39 $m^{2}$.

2. We have to find the area of the trapezoid.

(I'm not sure if the 9 is for the entire bottom side length)

• If the bottom side length is 9, then we would use the formula:

A = $\frac{a + b}{2} h$

to find the area of the entire trapezoid.

A = $\frac{2.4 + 9}{9}$ × 8.2

A ≈ 46.74 $mi^{2}$

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