3x^3+0x^2-2x+k:x-2=3x^2+6x+10
3x^2-6x^2
6x^2-2x
6x^2-12x
10x+k
10x-20
k+20
Thus k=-20
Assuming that the missing operations are multiplication as it is with the first question "bd", then the answer would be as follows:
1.) Simply substitute the values of b and d before multiplying.
bd = (-2)(-6) = 12
2.) (-50)(-2) = 100
3.) (5/8)(7/12)= 35/96
Answer:
1101 base 2
Step-by-step explanation:
you first take the larger number up the the lower number down
- 11010 -1101
- when dividing if it's zero you borrow one from the number on the left hand side
- since it's in base 2 the number you borrow would be 2 then u subtract
- I hoped it helped u
Answer: There 225 3-digit numbers multiple of 4