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Brrunno [24]
3 years ago
5

Find the greatest common factor of 26 and 14​

Mathematics
2 answers:
Jlenok [28]3 years ago
8 0
The gcf is 2 hope this helps
Nookie1986 [14]3 years ago
6 0
The greatest common factor of 26 and 14 is 2.
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I subtract 3 from a certain number, multiply the result by 5 and then add 9 if the final result is 54. find the original number
Sergeu [11.5K]

(x-3)\cdot 5+9=54\\5x-15=45\\5x=60\\x=12

8 0
2 years ago
-17/40 as a decimal show how pls
creativ13 [48]

Answer:

-0.425

Step-by-step explanation:

-0.425

7 0
2 years ago
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Why in division there is sometimes remaindres?
Ksenya-84 [330]
In division problems, if the division results in a decimal or fraction, (not a whole number), than it has a remainder.  If the division results in a whole number, then there is no remainder, or a remainder of zero. 

Examples:

6/3=2

6/4=1.5
7 0
3 years ago
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✨ B R A I N L I E S T
miv72 [106K]

1

:x

2

+y

2

−6x−9y+13=0

(x−3)

2

+(y−

2

9

)

2

−9−

4

81

+13=0

(x−3)

2

+(y−

2

9

)

2

=

4

65

Here,

r

1

=

2

65

C

1

=(3,

2

9

)

Equation of another circle-

S

2

:x

2

+y

2

−2x−16y=0

(x−1)

2

+(y−8)

2

−1−64=0

(x−1)

2

+(y−8)

2

=65

Here,

r

2

=

65

C

2

=(1,8)

Distance between the centre of two circles-

C

1

C

2

=

(3−1)

2

+(8−

2

9

)

2

C

1

C

2

=

4+

4

49

=

2

65

∣r

2

−r

1

∣=

∣

∣

∣

∣

∣

∣

65

−

2

65

∣

∣

∣

∣

∣

∣

=

2

65

∵C

1

C

2

=∣r

1

−r

2

∣

Thus the two circles touches each other internally.

Since the circle touches each other internally. The point of contact P divides C

1

C

2

externally in the ratio r

1

:r

2

, i.e.,

2

65

:

65

=1:2

Therefore, coordinates of P are-

⎝

⎜

⎜

⎜

⎜

⎜

⎛

1−2

1(1)−2(3)

,

1−2

1(8)−2(

2

9

)

⎠

⎟

⎟

⎟

⎟

⎟

⎞

=(5,1)

Therefore,

Equation of common tangent is-

S

1

−S

2

=0

(5x+y−6(

2

x+5

)−9(

2

y+1

)+13)−(5x+y−2(

2

x+5

)−16(

2

y+1

))=0

2

−6x−9y−13

+x+8y+13=0

4x−7y−13=0

Hence the point of contact is (5,1) and the equation of common tangent is 4x−7y−13=0.

4 0
2 years ago
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Lucy’s parents built a swimming pool in the backyard. Use 3.14 for π.
Neporo4naja [7]

Answer:

Distance around the pool = 162.8 feet

Area of the pool = 957 square feet

Step-by-step explanation:

Distance around the swimming pool = Perimeter of the pool

Perimeter of the pool which is a composite figure will be,

= Circumference of the semicircle + Sum of three sides of the pool

= πr + 2×(length of the pool) + width of the pool

= 3.14×(10) + 2×40 + 20

= 62.8 + 80 + 20

= 162.8 ft

Area of the pool = Area of the semicircle + Area of the rectangular pool

                           = \frac{1}{2}(\pi)(r)^{2}+(\text{length}\times \text{Width})

                           = \frac{1}{2}(3.14)(10)^2+(40\times 20)

                           = 157 + 800

                           = 957 square feet

8 0
3 years ago
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