Answer:
im pretty sure its the 3rd one
To solve this problem, let us recall that the formula for
probability is:
Probability = total number of successful events / total
events
Where in this case, an event is considered to be successful
if the sum is 3 on the pair of six sided dice.
First, let us calculate for the total number of events. There
are 6 numbers per dice, therefore the total number of combinations is:
total events = 6 * 6 = 36
Next, we calculate for the total number of combinations
that result in a sum of 3. We can identify that there are only two cases that
result in sum of 3. That is:
1st case: first dice rolls 1, second dice
rolls 2
2nd case: first dice rolls 2, second dice
rolls 1
Hence, total number of successful events = 2. Therefore the
probability is:
Probability = 2 / 36 = 1 / 18 = 0.0556 = 5.56%
I'm may not be that good at math, but I'm going to try my best to help you, because I know how it feels to be in this situation!
The first one :
You might be right on D. But I'm thinking B also. The question asks "Which could be a cross section of a rectangular pyramid that has been intersected by a plane perpendicular". But a triangle is basically a flat pyramid.
(I'm typing really fast to help!!!!)
Second one: Its B!! Look at it really closely! You'll get it!!!
(Going really fast now!!!!)
Third one: Between B or D!!! But I think you're right on your choice!!!!
(FASTER FASTER!!!)
FINALLY: Copy and paste your answers into google. People have asked the same question!
I hope I helped. I don't want to make you fail, as I am in the SAME similar situation as you! I really REALLY REALLY HOPE YOU PASS!!!
The area of the trapezoid is given by:
A = (1/2) * (b1 + b2) * (h)
Where,
b1, b2: bases of the trapezoid
h: height
Substituting values we have:
91 = (1/2) * ((2 * 7) + b2) * (7)
Rewriting we have:
91 = (1/2) * (14 + b2) * (7)
(2/7) * 91 = 14 + b2
b2 = (2/7) * 91 - 14
b2 = 12 m
Answer:
The measure of the other base of the trapezoid is:
b2 = 12 m
